A bug was running along a number line at a speed of 11 units per minute. It never changed its direction. If at 7:15 it was at th

Question

3 years ago

9

e point 100, where could it be at 7:20 pm? The bug will be on the point or at 7:20Pm

2 answers:

barxatty [35] · Answer 1 · 2022-10-02T12:27:57+03:00

Answer:

155 Units

Step-by-step explanation:

Rate of Bug (given) = 11 units PER MINUTE

It never changed direction, so it was going in positive direction (assume).

In 7:15 pm (evening), it was at Point 100,

We want the point at which it was at 7:20 pm.

7:20pm - 7:15pm = 5 minutes

So, time passed 5 minutes. It's rate is 11 units PER MINUTE, so in 5 mins:

11 * 5 = 55 units

Assuming he is going in positive direction, the bug will be at:

100 + 55 = 155 Units

adoni [48] · Answer 2 · 2022-10-02T14:39:02+03:00

Answer:

It will be at the point 155

Step-by-step explanation:

It will be at point 155 If it keeps running at the same pace and in the same direction.

I know this because if it is at point 100 at 7:15 and it goes 11 units per minute then 5 minutes later at 7:20 it would be at point 155