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alex41 [277]
3 years ago
9

A bug was running along a number line at a speed of 11 units per minute. It never changed its direction. If at 7:15 it was at th

e point 100, where could it be at 7:20 pm? The bug will be on the point or at 7:20Pm
Mathematics
2 answers:
barxatty [35]3 years ago
8 0

Answer:

155 Units

Step-by-step explanation:

Rate of Bug (given) = 11 units PER MINUTE

It never changed direction, so it was going in positive direction (assume).

In 7:15 pm (evening), it was at Point 100,

We want the point at which it was at 7:20 pm.

7:20pm - 7:15pm = 5 minutes

So, time passed 5 minutes. It's rate is 11 units PER MINUTE, so in 5 mins:

11 * 5 = 55 units

Assuming he is going in positive direction, the bug will be at:

100 + 55 = 155 Units

adoni [48]3 years ago
4 0

Answer:

It will be at the point 155

Step-by-step explanation:

It will be at point 155 If it keeps running at the same pace and in the same direction.

I know this because if it is at point 100 at 7:15 and it goes 11 units per minute then 5 minutes later at 7:20 it would be at point 155

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Step-by-step explanation:

First, isolate the variables onto one side of the equation.

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Hello!


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