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3 years ago

Please please help me out with this!!!

Mathematics

2 answers:

BabaBlast [244]3 years ago

7 0

The answer is Graph C.

nlexa [21]3 years ago

6 0

The correct answer is D

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Help me please!! I don’t know

VLD [36.1K]

Answer:

You have the right answer what do you need help with?

Step-by-step explanation:

3 0

3 years ago

Read 2 more answers

Two planes left simultaneously from the same airport and headed in the same direction towards another airport 3600 km away. The

ExtremeBDS [4]

Answer:

800 kph
600 kph

Step-by-step explanation:

Equation

Let s represent the speed of the faster plane. Then its travel time is ...

time = distance/speed = 3600/s

travel time for the slower plane is ...

time = distance/speed = 3600/(s -200)

The difference in these times is 1.5 hours, so we have ...

3600/(s -200) -3600/s = 1.5

Solution

Multiplying by (2/3)s(s -200), we get ...

2400(s) -2400(s -200) = s(s -200)

s^2 -200s -480000 = 0 . . . . . . . . . . rewrite in standard form

(s -800)(s +600) = 0 . . . . . . . . . . . . . factor

The positive value of s that makes a factor zero is s = 800.

Conclusion

The speed of the faster plane was 800 km/h; of the slower plane, 600 km/h.

_____

Check

The travel time for the faster plane was 3600/800 = 4.5 hours. For the slower plane, 3600/600 = 6 hours, a difference of 1.5 hours.

6 0

2 years ago

What is the domain of the square root function graphed below?

Nikolay [14]

The domain of a function is the set of all values x can have.
From the graph, we see the least value of x is 3. x can be any value greater than or equal to 3.

The domain is

$x \ge 3$

5 0

3 years ago

Can someone help me please// this is a music question btw

Zolol [24]

A and d I believe..............

7 0

2 years ago

Suppose that

Diano4ka-milaya [45]

Answer:

sin(B) = 12/13

cos(B) = 5/13

tan(B) = 12/5

csc(B) = 13/12

sec(B) = 13/5

cot(B) = 5/12

Step-by-step explanation:

If ABC is a right triangle, assuming that ∠C = 90°, then the segment AB =13 is the hypotenuse and the other two sides are:

$BC = 5\\AC = \sqrt{13^2 - 5^2}\\AC = 12$

The six trigonometric functions of angle B are:

$sin(B) =\frac{AC}{AB}= \frac{12}{13}\\cos(B) = \frac{BC}{AB} =\frac{5}{13}\\tan(B) = \frac{AC}{BC} =\frac{12}{5}\\\csc(B) =\frac{1}{sin(B)}= \frac{13}{12}\\sec(B) = \frac{1}{cos(B)} =\frac{13}{5}\\cot(B) = \frac{1}{tan(B)} =\frac{5}{12}\\$

7 0

3 years ago