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pashok25 [27]
3 years ago
14

How do write this problem out?

Mathematics
1 answer:
KATRIN_1 [288]3 years ago
4 0
(x^2-3x)-(x-3)
x(x-3)-1(x-3)
(x-1)(x-3)
I think
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How many one-thirds are in one-sixth?
andrew11 [14]

there are (1/6)/(1/3) one-third in one sixth

Step-by-step explanation:

that means

no. of one-third is 1/2

4 0
2 years ago
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Find the area of the shaded region to the nearest tenth. See picture for full problem. Please and thank you so much!
Anestetic [448]

Answer:

Step-by-step explanation:

Radius =6 ft

Area of circle = πr²

                      = 3.14 * 6 * 6

                      = 113.04 ft²

base = 10.39 ft

height = 6+3 = 9 ft

Area \ of \ triangle = \dfrac{1}{2}*base * height\\\\\\=\dfrac{1}{2}*10.39*9\\

= 46.76 ft²

Area of the shaded region = area of circle - area of triangle

             = 113.04 - 46.76

            = 66.28

             = 66.3 ft²

8 0
2 years ago
Find the nth term of this 5 7 9 11 13
NemiM [27]
Firstly, seeing that the sequence is based on odd numbers I would say that this is the formula (which will allow you to know whatever term):

nth term = 2n-1

Hope this helps!
4 0
2 years ago
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Oliver had m dollars to spend on a backpack for the new school year. The expression below represents the amount of money he had
xxMikexx [17]

Answer:

Option A

Step-by-step explanation:

Y is the amount of back pack

The total amount is represented by m

If Y is the cost of back pack purchased by Oliver, then 0.7 Y is the tax applicable on the purchase of back pack

Hence, the remaining cost would be total amount with Oliver minus the cost of back pack and the tax applicable on the purchase of back pack

Remaining cost  = m - (y + 0.07y)

Hence, option A is correct

6 0
2 years ago
At noon, ship A is 50 km west of ship B. Ship A is sailing south at 10 km/h and ship B is sailing north at 20 km/h. How fast is
Lena [83]
So  hmmm check the picture below

so, we're looking for dr/dt then at 4:00pm or 4 hours later

now, keep in mind that, the distance "x", is not changing, is constant whilst "y" and "r" are moving, that simply means when taking the derivative, that goes to 0

\bf r^2=x^2+y^2\implies 2r\cfrac{dr}{dt}=0+2y\cfrac{dy}{dt}\implies \cfrac{dr}{dt}=\cfrac{y\frac{dy}{dt}}{r}\quad 
\begin{cases}
\cfrac{dy}{dt}=30\\
r=130\\
y=120
\end{cases}
\\\\\\
\cfrac{dr}{dt}=\cfrac{120\cdot 30}{130}

6 0
3 years ago
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