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pashok25 [27]
3 years ago
14

How do write this problem out?

Mathematics
1 answer:
KATRIN_1 [288]3 years ago
4 0
(x^2-3x)-(x-3)
x(x-3)-1(x-3)
(x-1)(x-3)
I think
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A recent survey of 400 pet owners reveals that the ratio of cat owners to dog owners is 4 to 5. If there are 500 registered cat
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Do 500 divied by 4 and its 125  so 125 people have dogs.
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Step-by-step explanation:

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3 years ago
What is a "confound" in an experimental study? Group of answer choices
Ostrovityanka [42]

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The correct option is <u><em>option a. an extra variable that could explain result differences between groups.</em></u>

Step-by-step explanation:

Confusion variables, also called third variables, are variables that the investigator did not control or did not eliminate and that damage the internal validity of an experiment, that is, the degree to which the results are valid.

The dependent and independent variables are the two main variables of any experiment or investigation. The independent is one that changes or is controlled to study its effects on the dependent variable. The dependent is that variable that is investigated and measured.

Confusion variables may cause the investigator to analyze the results incorrectly. The results may show a false correlation between dependent and independent variables.

So <u><em>the correct option is option a. an extra variable that could explain result differences between groups.</em></u>

This is because this additional variable that was not controlled or taken into account during the experimental study modifies the result. And the other groups that conducted the experiment and took into account the variable will have different results because they take into account other independent variables.

3 0
3 years ago
An element with mass 510 grams decays by 26.3% per minute. How much of the element is remaining after 7 minutes, to the nearest
Eddi Din [679]

A decay rate of 26.3% per minute means that for every minute that passes, there remains 73.7% of the amount of the substance available at the end of the previous minute.

If a_0 is the starting amount, and a_i is the amount left after i minutes, then

a_1=0.737a_0

a_2=0.737a_1=0.737^2a_0

a_3=0.737a_2=0.737^3a_0

and so on, such that

a_7=0.737^7a_0

We have a_0=510 grams at the start, so after 7 minutes we're left with

a_7=0.737^7(510)\approx60.2\,\rm g

4 0
3 years ago
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