Answer:
Step-by-step explanation:
Given the values of the actual content of protein powder recorded as shown:
1530, 1532, 1495, 1508, 1528, and 1511
a) We are to find the mean and median of the contents.
Mean is the average sum of the numbers. It is expressed mathematically as xbar = ΣXi/N
Xi are individual values
N is the total number of values present.
N = 6
xbar = (1,530+1,532+1,495 +1,508+1,528+1,511)/6
xbar = 9104/6
xbar = 1517.33
Median of the data is the value at the middle after rearrangement. On rearranging from lowest to highest:
1,495, 1508, 1511, 1528, 1530, 1532
The two values at the centre are 1511 and 1528.
Median = 1511+1528/2
Median = 1519.5
b) If the third value was incorrectly measured and is actually 1515, then our new data will become.
1530, 1532, 1515, 1508, 1528, and 1511
xbar = (1,530+1,532+1,515 +1,508+1,528+1,511)/6
xbar = 9124/6
xbar = 1520.67
For median:
We arrange first
1508, 1511, 1515, 1528, 1530, 1532
The two values at the centre are 1515 and 1528.
Median = 1515+1528/2
Median = 1521.5
c) To know the measure of central tendency that was most affected, we will look at the difference in the values gotten for both mean and median.
∆Mean = 1520.67-1517.33
∆Mean = 3.34
∆Median = 1521.5 - 1519.5
∆Median = 2.0
It can be seen that the measure of central tendency with greater deviation is the mean. Therefore, the mean is more affected by the data entry error.
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