Answer:
284cm^2
Step-by-step explanation:
first, we split up the shape into seperate sections that we can easily find the areas of.
i will draw vertical lines in the bottom left and right, leaving me with 2 seperate rectangles and 1 irregular pentagon.
we know that these rectangles are 4x8cm, so we do 4 * 8 which gives us 32.
there are 2 of these, so 32 x 2 = 64cm^2.
now, i chose to seperarte the pentagon into a rectangle and a triangle,
and i found the height and width of the rectangle to be (18 - (4+4)) x (8+7), or 10 x 15.
the area of the rectangle is 150cm^2.
now, for the triangle.
the line through the centre of th shape is 22cm long, but we only want the part in the triangle. luckily, there are mesurements that can help us with this.
8 + 7 = 15.
22 - 15 = 7.
now we know that the height of the triangle is 7 cm.
from earlier, we also know the base, which is 10cm.
7 x 10 = 70cm^2.
now we add all these together:
70 + 150 + 64 = 284cm^2
To solve this problem you must apply the proccedure shown below:
1. You have:
<span>
In(2x+3)=7
2. Then, you must apply log(e), as below:
</span><span>
In(2x+3)=ln(e^7)
3. Now, you obtain:
2x+3=e^7
4. Youy must clear the variable "x", as below:
2x=e^7-3
</span> x=(e^7-3)/2
<span>
5. Therefore, the value of "x" is:
x=546.817
</span><span>
The answer is: </span>x=546.817<span> </span>
Answer:
6.00
Step-by-step explanation:
Answer:
m=13/2 hope this helped:)
Step-by-step explanation:
Answer:
3/11
Step-by-step explanation:
