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3 years ago

IS 6 A TERM IN 12p+6

2 answers:

7 0

Yes, because since a term is separated by an addition or subtraction sign (not multiplication, but I'm not sure for division). Therefore, 6 is separated from 12p, so it's a term.

marusya05 [52]3 years ago

4 0

Yes, 6 is one of the terms in the equation

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A season ticket to the olde theater costs $76 and admits you to 6 plays. single tickets to each play cost $15. how much do you s

Maksim231197 [3]

Answer:

Step-by-step explanation:

6×15=90 90-76=14 you save 14 dollars

4 0

3 years ago

What is 2x-64<108 If you answer this I will give you a total of 23 points!

alexandr1967 [171]

Answer:

2x-64<108

One solution was found :

x < 86

Rearrange:

Rearrange the equation by subtracting what is to the right of the greater than sign from both sides of the inequality :

2*x-64-(108)<0

Step by step solution :

Step 1 :

Pulling out like terms :

1.1 Pull out like factors :

2x - 172 = 2 • (x - 86)

Equation at the end of step 1 :

Step 2 :

2.1 Divide both sides by 2

Solve Basic Inequality :

2.2 Add 86 to both sides

x < 86

4 0

3 years ago

How many whole numbers are there with not more than 4 digits?

Flauer [41]

I think its 1000 numbers because there from 1 to 999 there are 999 numbers, and then you add zero because it is also a whole number.

7 0

3 years ago

Read 2 more answers

16) Please help with question. WILL MARK BRAINLIEST + 10 POINTS.

Katyanochek1 [597]

We will use the sine and cosine of the sum of two angles, the sine and consine of $\frac{\pi}{2}$ , and the relation of the tangent with the sine and cosine:

$\sin (\alpha+\beta)=\sin \alpha\cdot\cos\beta + \cos\alpha\cdot\sin\beta

\cos(\alpha+\beta)=\cos\alpha\cdot\cos\beta-\sin\alpha\cdot\sin\beta$

$\sin\dfrac{\pi}{2}=1,\ \cos\dfrac{\pi}{2}=0$

$\tan\alpha = \dfrac{\sin\alpha}{\cos\alpha}$

If you use those identities, for $\alpha=x,\ \beta=\dfrac{\pi}{2}$ , you get:

$\sin\left(x+\dfrac{\pi}{2}\right) = \sin x\cdot\cos\dfrac{\pi}{2} + \cos x\cdot\sin\dfrac{\pi}{2} = \sin x\cdot0 + \cos x \cdot 1 = \cos x$

$\cos\left(x+\dfrac{\pi}{2}\right) = \cos x \cdot \cos\dfrac{\pi}{2} - \sin x\cdot\sin\dfrac{\pi}{2} = \cos x \cdot 0 - \sin x \cdot 1 = -\sin x$

Hence:

$\tan \left(x+\dfrac{\pi}{2}\right) = \dfrac{\sin\left(x+\dfrac{\pi}{2}\right)}{\cos\left(x+\dfrac{\pi}{2}\right)} = \dfrac{\cos x}{-\sin x} = -\cot x$

3 0

4 years ago

The Suarez family paid $12.75 for 3 movie tickets. How much would they have paid for 12 tickets?

77julia77 [94]

Answer:

51 dollars

Step-by-step explanation:

4 times 12.75 =51

8 0

3 years ago

Read 2 more answers