ST is a midsegment, which tells you that BD=2(ST) or ST=½BD. Use that to substitute the values and find ST.
BD=2(ST)
29+x=2(2x+31)
29+x=4x+62
29=3x+62
-33=3x
x=-11
Now that we know x, we can substitute that into 2x+31 to find ST
ST=2x+31
ST=2(-11)+31
ST=-22+31
ST=9
Answer:
same
Step-by-step explanation:
hope this helps
Make sure that you are looking at the right boxes
Area of the whole circle = 3.14 * 7.5^2
area of the sector = (3.14 * 7.5^2 * 210) / 360
= 103 cn^2 to nearest whole number
Y = kx
Plug in what we know:
5 = k(8)
5 = 8k
Divide 8 to both sides:
k = 0.625
Plug this back into the equation along with y = 15:
y = kx
15 = 0.625x
Divide 0.625 to both sides:
x = 24