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3 years ago

If you roll two fair six-sided dice, what is the probability that both dice show an odd number?

Mathematics

1 answer:

geniusboy [140]3 years ago

7 0

It would be 50 percent or .5 the chances of odd would be 3/6 so 3/6*3/6 would be half of each dice. so 50% i believe

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2 5/16 divided into 7/8 equals what

Whitepunk [10]

Answer:

4 1/14

Step-by-step explanation:

2 5/16=57/16

57/16*8/7=57/16 divided by 7/8

57/16*8/7=57/2*7=57/14=4 1/14

8 0

2 years ago

Use the fundamental identities and appropriate algebraic operations to simplify the following expression. (18 +tan x) (18-tan x)

andrezito [222]

Answer:

a) $\left(18+\tan \left(x\right)\right)\left(18-\tan \left(x\right)\right)+\sec ^2\left(x\right)=325$

b) The lowest point of $y=\cos \left(x\right)$ , $0\leq x\leq 2\pi$ is when x = $\pi$

Step-by-step explanation:

a) To simplify the expression $\left(18+\tan \left(x\right)\right)\left(18-\tan \left(x\right)\right)+\sec ^2\left(x\right)$ you must:

Apply Difference of Two Squares Formula: $\left(a+b\right)\left(a-b\right)=a^2-b^2$

$a=18,\:b=\tan \left(x\right)$

$\left(18+\tan \left(x\right)\right)\left(18-\tan \left(x\right)\right)=18^2-\tan ^2\left(x\right)=324-\tan ^2\left(x\right)$

$324-\tan ^2\left(x\right)+\sec ^2\left(x\right)$

Apply the Pythagorean Identity $1+\tan ^2\left(x\right)=\sec ^2\left(x\right)$

From the Pythagorean Identity, we know that $1=-\tan ^2\left(x\right)+\sec ^2\left(x\right)$

Therefore,

$324[-\tan ^2\left(x\right)+\sec ^2\left(x\right))]\\324[+1]\\325$

b) According with the below graph, the lowest point of $y=\cos \left(x\right)$ , $0\leq x\leq 2\pi$ is when x = $\pi$

3 0

3 years ago

Solve for I when 3/5 +I-1/15

Ugo [173]

Answer:

23 over 15 or 1.533

Step-by-step explanation:

Group like terms:

1+(3/5+-1/15)

Find LCD:

1+9/15+-1/15

Combine numerators:

15/15+8/15

And you get 23/15

Simplified:1 8/15

Decimal: 1.533

4 0

2 years ago

Four more than the quotient of a number and 3 is 9

barxatty [35]

The algebraic expression of "Four more than the quotient of a number and 3 is 9" is $\frac{x}{3}+4=9$

The value of x=15

Step-by-step explanation:

We need to express "Four more than the quotient of a number and 3 is 9" as algebraic expression.

Let the number = x

Solving:

quotient of a number and 3: $\frac{x}{3}$

Four more than the quotient of a number and 3: $\frac{x}{3}+4$

Four more than the quotient of a number and 3 is 9: $\frac{x}{3}+4=9$

Now, finding value of x:

$\frac{x}{3}+4=9\\Adding\,\,-4\,\,on\,\,both\,\,sides:\\\frac{x}{3}+4-4=9-4\\\frac{x}{3}=5\\Multiply\,\,both\,\,sides\,\,by\,\,3:\\x=5*3\\x=15$

So, value of x = 15

Keywords: Algebraic expression

Learn more about algebraic expression at:

#learnwithBrainly

4 0

2 years ago

What’s the answer? Pls help soon

Vilka [71]

You get this or no??

6 0

2 years ago

Read 2 more answers