we have
y > -2
x + y < 4
using a graph tool
see the attached figure
The shaded area is the solution of the system
<u>Part 1) </u>Name an ordered pair that is a solution to this system and explain how you know that this is a solution point
Let
A ( -40,20)
The point A is solution of the system because the point lie on the shaded area
<u>Check</u>
If the point A is solution of the system must satisfy both system inequalities
point A
x=-40
y=20
substitute
y > -2-------> 20 > -2-------> is ok
x + y < 4----> -40+20 < 4-----> -20 < 4-----> is ok
therefore
<u>the answer Part 1) is</u>
The point A is a solution of the system
Part 2) Name an ordered pair that is not a solution to the system and explain how you know that it is not a solution
Let
B(20,20)
The point B is not solution of the system because the point not lie on the shaded area
<u>Check</u>
If the point B is not solution of the system must not satisfy both system inequalities
point B
x=20
y=20
substitute
y > -2 -------> 20 > -2-------> is ok
x + y < 4---->20+20 < 4-----> 40 < 4------> is not ok
therefore
<u>the answer part 2) is</u>
The point B is not a solution to the system
R = { (x,y): 3x-y=0 }
The condition is 3x=y so that's not going to be any of these things.
R is reflexive if (x,x)∈R for all x. Let's check.
3x - y = 3x - x = 2x ≠ 0 necessarily. NOT REFLEXIVE
R is symmetric if (x,y)∈R → (y,x)∈R. Let's check.
(x,y)∈R so
3x-y = 0
y = 3x
Is (y,x)∈R. That would be true if 3y-x=0
3y - x = 3(3x) - x = 8x ≠ 0 necessarily NOT SYMMETRIC
R is transitive if (x,y)∈R and (y,z)∈R → (x,z)∈R. Let's check.
3x-y = 0 so y=3x
3y-z = 0 so z=3y = 9x
3x - z = 3x - 9x = -6x ≠ 0 necessarily NOT TRANSITIVE
The answer is 50x-35.hope this helps.if it does please mark brainliest
The answer is D
Explanation)
Multiplication identity property is when a factor is multiplied by 1
I think it is 210
because 15x14=210