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3 years ago

Someone please answer this question for me?

Mathematics

1 answer:

densk [106]3 years ago

8 0

c = the number of chocolate chips bags

2.75c + 3.59

[costs $2.75 for each bag of chocolate chips (c) plus one bag of flour $3.59, since she will need only one bag of flour and an unknown number of bags of chocolate chips]

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Using the following uniform density curve, answer the question.

Vesnalui [34]

Answer:

The answer is "0.4125"

Step-by-step explanation:

$\to 7.4 -4.1= 3.3 (0.125)= 0.4125$

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3 years ago

Yolanda left for a youth retreat at 8:00 p.m. On Friday. She came home on Sunday morning at 10:00 a.m. How long was Yolanda away

weeeeeb [17]

Yolanda was gone for 12 hours

6 0

4 years ago

Read 2 more answers

Please I Need Help !

SOVA2 [1]

Answer:

Basically, this Marco forgot to jump another ten and instead of 325 it's 335.

Step-by-step explanation:

you have to first find the difference then see how the number is 335? You jump 300 spaces, then 30, then five :3.

4 0

3 years ago

What’s the x and y intercept of 8x+5y=-48

Anuta_ua [19.1K]

Step-by-step explanation:

$8x + 5y = - 48 \\ \\ at \: x = 0 \\ \\ 8 \times 0 + 5y = - 48 \\ \\ \therefore \: 5y = - 48 \\ \\ \therefore \: y = \frac{ - 48}{5} \\ \\ \therefore \: y - intercept = - 9.6 \\ \\ at \: y = 0 \\ \\ 8 x + 5 \times 0 = - 48 \\ \\ \therefore \:8x = - 48 \\ \\ \therefore \: x = \frac{ - 48}{8} \\ \\ \therefore \: x - intercept = -6 \\ \\$

4 0

4 years ago

Determine the equation of a line in standard form that represents alanas training progress. Her progress points corresponds to t

elixir [45]

Answer:

The equation of the line passing through the above points is:

$y=-\frac{1}{2}x+\frac{29}{2}$

Step-by-step explanation:

Given:

The two points are: $(x_1,y_1)=(1,14)\textrm{ and }(x_2,y_2)=(9,10)$

The equation of a line when two points are given is:

$y-y_1=\left (\frac{y_2-y_1}{x_2-x_1} \right )(x-x_1)$

Plug in all the values and simplify.

$y-14=\left (\frac{10-14}{9-1} \right )(x-1)\\y-14=\left (\frac{-4}{8} \right )(x-1)\\y-14=-\frac{1}{2}(x-1)\\y-14=-\frac{1}{2}x+\frac{1}{2}\\y=-\frac{1}{2}x+\frac{1}{2}+14\\\\\\y=-\frac{1}{2}x+\frac{29}{2}$

Therefore, the equation of the line passing through the above points is:

$y=-\frac{1}{2}x+\frac{29}{2}$

8 0

3 years ago