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Mashcka [7]
3 years ago
14

5-(x/3)when x=12 What’s the answer

Mathematics
2 answers:
patriot [66]3 years ago
8 0

Answer:1

Step-by-step explanation:

notka56 [123]3 years ago
4 0

Answer:

When x is 12<em>, </em>5-(\frac{x}{3})=1

Step-by-step explanation:

5-(\frac{x}{3} )

Insert the given value of x:

5-(\frac{12}{3} )

Simplify the expression. Divide 12 by 3:

5-4

Simplify subtraction:

1

:Done

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Joey and his family are taking a road trip. On Monday they travel 68 miles. On Tuesday , they travel 25 miles. On Wednesday they
Stolb23 [73]

Answer:

42 miles

Step-by-step explanation:

so average is found by taking the sum of numbers of all the numbers given, and dividing by the number of numbers

so

68+25+33= 126

126/3=42

they drove an avg of 42 miles

hope this helps

6 0
3 years ago
Help me with which triangle it is and how do I find x?
3241004551 [841]

Answer:

isosceles

x=14

Step-by-step explanation:

isosceles because of the two I symbols on the triangle

x+5=2x-9

5+9=2x-x

14=x

6 0
3 years ago
Read 2 more answers
7. All quadrilaterals have 4 sides and a trapezoid is a quadrilateral. How many sides does a trapezoid have? A: 5 B: 4 C: 3 D: 2
nata0808 [166]

Answer:

B: 4

Step-by-step explanation:

A trapezoid have 4 sides.

Hope it helps you in your learning process

5 0
2 years ago
Read 2 more answers
1+secA/sec A = sin^2 A / 1-cos A​
Fofino [41]

Answer:  see proof below

<u>Step-by-step explanation:</u>

\dfrac{1+\sec A}{\sec A}=\dfrac{\sin^2 A}{1-\cos A}

Use the following Identities:

sec Ф = 1/cos Ф

cos² Ф + sin² Ф = 1

<u>Proof LHS → RHS</u>

\text{LHS:}\qquad \qquad \dfrac{1+\sec A}{\sec A}

\text{Identity:}\qquad \qquad \dfrac{1+\frac{1}{\cos A}}{\frac{1}{\cos A}}

\text{Simplify:}\qquad \qquad \dfrac{\frac{\cos A+1}{\cos A}}{\frac{1}{\cos A}}\\\\\\.\qquad \qquad \qquad =\dfrac{1+\cos A}{1}

\text{Multiply:}\qquad \qquad \dfrac{1+\cos A}{1}\cdot \bigg(\dfrac{1-\cos A}{1-\cos A}\bigg)\\\\\\.\qquad \qquad \qquad =\dfrac{1-\cos^2 A}{1-\cos A}

\text{Identity:}\qquad \qquad \dfrac{\sin^2 A}{1-\cos A}

\text{LHS = RHS:}\quad \dfrac{\sin^2 A}{1-\cos A}=\dfrac{\sin^2 A}{1-\cos A}\quad \checkmark

3 0
3 years ago
Find the value of each value
amid [387]
W+2=3
w=3-2
so the answer is w=1
7 0
3 years ago
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