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Nat2105 [25]
3 years ago
14

Every morning, halle goes to school with a 1-liter bottle of water. she drinks 1/4 of the bottle before school starts and 2/3 of

the rest before lunch. what fraction of the bottle does halle drink after school starts but before lunch?
Mathematics
1 answer:
Nuetrik [128]3 years ago
8 0
I think it's 1/6. Because before school she drinks 1/4 then before lunch she drink 2/3 if 1/4 so you would multiply. 1*2=2. 4*3=12. So you get 2/12 or if you simplify, 1/6
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To calculate the percentage discount between two prices, follow these steps:

  1. Subtract the post-discount price from the pre-discount price.
  2. Divide this new number by the pre-discount price.
  3. Multiply the resultant number by 100.
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The price of a toy usually costing £50 is increases to £65<br> work out the percentage increase
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30%

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A musical group is putting on show at the theatre. They collected $880 from 120 people attending. The price of an adult ticket i
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7 0
3 years ago
What is the average rate of change of f over the interval -7 &lt; or equal to x Give an exact number
Annette [7]

Answer:

\frac{4}{3}

Step-by-step explanation:

The average rate of change can be found by using the following formula

\frac{f(x_{2}) - f(x_{1}) }{x_{2} - x_{1}}

Since the interval goes from -7 to 2, we should find the y-values that correspond to x=-7 and x=2.

By inspection of the graph, we can clearly see that when x is -7, y is -7 as well and when x is 2, y is 5.

Now that we know this, we can simply plug these values into the formula!

\frac{f(2) - f(-7) }{2 - (-7)} = \frac{5 - (-7)}{2 - (-7)} = \frac{5 +7}{2+7} = \frac{12}{9} = \frac{4}{3}

Good luck!

3 0
3 years ago
find the work done by a person pushing a 40 pound box up an incline that is 30 degrees above the horizontal and 100 feet long (i
tankabanditka [31]

The work done in pushing the box is 64000 lb-ft²/s²

<h3>How to calculate the work done by the person?</h3>

Since person pushing a 40 pound box up an incline that is 30 degrees above the horizontal and 100 feet long, the work done, W is

W = mgh where

  • m = mass of box = 40 lb,
  • g = acceleration due to gravity = 32 ft/s² and
  • h = height of incline = LsinФ where
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  • Ф = angle of incline = 30°

So, W = mgh

W = mgLsinФ

So, substituting the values of the variables into the equation, we have

W = mgLsinФ

W = 40 lb × 32 ft/s² × 100 ftsin30°

W = 1280 lb-ft/s² × 100 ft × 0.5

W = 1280 lb-ft/s² × 50 ft

W = 64000 lb-ft²/s²

So, the work done in pushing the box is 64000 lb-ft²/s²

Learn more about work done here:

brainly.com/question/25970931

#SPJ1

3 0
2 years ago
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