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Yakvenalex [24]
3 years ago
11

Can u help me I am so stuck on it

Mathematics
1 answer:
vichka [17]3 years ago
7 0
It is not clear what you need to do with this equation. For starters, you can simplify it:

3a + 5t + 3 -a + 6 + 4t = 2a +9t + 9

But that's about all you can do. You can't solve a and t, because for that you need another equation. For solving 2 variables, you need at least 2 equations.
You might be interested in
1) If y = x3 + 2x and dx/ dt = 5, find dy/dt when x = 2. Give only the numerical answer. For example, if dy, dt = 3, type only 3
Semenov [28]

Answer:

a) 70

b) 10π ft²/ft

c) 0.24 ft/sec

Step-by-step explanation:

1) y = x³ + 2x

\frac{dy}{dt}=\frac{d(x^3+2x)}{dt}

or

\frac{dy}{dt} = 3x^2\frac{dx}{dt}+2\frac{dx}{dt}

at \frac{dx}{dt}=5  and x = 2

\frac{dy}{dt} = 3(2)^2\times(5)+2\times(5)

or

\frac{dy}{dt} = 60 + 10 = 70

2) A = πr² ft²

\frac{dA}{dr}=\frac{d(\pi r^2)}{dr}

or

\frac{dA}{dr}= 2(πr)

at r = 5 ft

\frac{dA}{dr}= 2(π × 5) ft²/ft

or

\frac{dA}{dr}= 10π ft²/ft

3) From Pythagoras theorem

Base² + Perpendicular² = Hypotenuse²

Thus,

B² + P² = H²  .............(1)

here, H = length of the ladder

P is the height of the wall

B is the distance from the wall at bottom

or

B² + P² = 25²       ...........(1)  

at B = 20 ft

20² + P² = 25²        

or

P² = 625 - 400

or

P = √225

or

P = 15 ft

differentiating (1) with respect to time, we get

2B\frac{dB}{dt}+2P\frac{dP}{dt}=0

at B = 20 ft, \frac{dB}{dt} = 0.18 and P = 15 ft

⇒ 2(20)(0.18) + 2(15)\frac{dP}{dt} = 0

or

30\frac{dP}{dt} = - 7.2

or

\frac{dP}{dt} = - 0.24 ft/sec (Here negative sign depicts the ladder slides down)

7 0
4 years ago
The vertices of a right triangle are (6, 2), (–2, –4), and (–2, y).
lesya692 [45]
 Hello,

y=2

Answer C
==================


4 0
3 years ago
How can I get better at Division in 5th grade?
Vanyuwa [196]

Answer:

Practice!

Step-by-step explanation:

Seriously, ask friends or family for complete random questions. Ask your teacher for tips.

3 0
3 years ago
Read 2 more answers
A man is twice as old as his son. Five years ago, the ratio of their ages was 9:4. Find the son's present age
Sidana [21]

Answer:

Son's age is 25.

Step-by-step explanation:

Let the Father's age be 2x.

Let the son's age be x.

Five years ago:

Man's age will be = 2x - 5

Son's age will be = x - 5

If the ratio of their ages five years ago was 9:4, then:

2x - 5/x-5 = 9/4

⇒ 4(2x - 5) = 9(x - 5)

⇒ 8x - 20 = 9x - 45

⇒ -20 + 45 = 9x - 8x

⇒ 25 = x

∴ x = 25

Hence, the son's age = 25 years

If x = 25, the father's age (2x) will be 2 × 25 = 50 years

7 0
3 years ago
which of the following is the equation of a line in slop-intercept from a line with slope=2 and y-intercept at (0,3)
romanna [79]
The answer is Y=2x+3
3 0
3 years ago
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