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Alex777 [14]
3 years ago
10

A man is twice as old as his son. Five years ago, the ratio of their ages was 9:4. Find the son's present age

Mathematics
1 answer:
Sidana [21]3 years ago
7 0

Answer:

Son's age is 25.

Step-by-step explanation:

Let the Father's age be 2x.

Let the son's age be x.

Five years ago:

Man's age will be = 2x - 5

Son's age will be = x - 5

If the ratio of their ages five years ago was 9:4, then:

2x - 5/x-5 = 9/4

⇒ 4(2x - 5) = 9(x - 5)

⇒ 8x - 20 = 9x - 45

⇒ -20 + 45 = 9x - 8x

⇒ 25 = x

∴ x = 25

Hence, the son's age = 25 years

If x = 25, the father's age (2x) will be 2 × 25 = 50 years

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Use a graphing utility to graph the function and the damping factor of the function in the same viewing window.
Bas_tet [7]

Answer:

The function touches the damping factor

at x=\frac{(4n-3)\pi}{2} and x=\frac{(4n-1)\pi}{2}

The x-intercept of f(x) is

at x=n\pi

Step-by-step explanation:

Given function is f(x)=e^{-3x} sin(x) and damping factor as y=e^{-3x} and y=(-1)e^{-3x}

To find when function touches the damping factor:

For f(x)=e^{-3x} sin(x) and y=e^{-3x}

Equating the both the equation,

e^{-3x} sin(x)=e^{-3x}

sin(x)=1

x=\frac{(4n-3)\pi}{2}

For f(x)=e^{-3x} sin(x) and y=(-1)e^{-3x}

Equating the both the equation,

e^{-3x} sin(x)=(-1)e^{-3x}

sin(x)=(-1)

x=\frac{(4n-1)\pi}{2}

Therefore, The function touches the damping factor x=\frac{(4n-3)\pi}{2} and x=\frac{(4n-1)\pi}{2}

To find x-intercept of f(x):

For x-intercept, y=0

f(x)=e^{-3x} sin(x)

y=e^{-3x} sin(x)

e^{-3x} sin(x)=0

Hence, e^{-3x} is always greater than zero.

Therefore,sin(x)=0

x=n\pi

Thus,

The x-intercept of f(x) is at x=n\pi

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4 years ago
I need help with this question!!
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I need help please thanks​
ch4aika [34]
Same, highest exponent
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