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Hoochie [10]
3 years ago
8

You are purchasing an exercise machine for a physical therapy office. The machine has a 20 inch vertical space where you add wei

ghts to increase the resistance for the patient. Five pound weights are 3" high. Two pound weights are 1 ½" high. One pound weights are 1". How much weight can the machine hold?
Mathematics
1 answer:
Zolol [24]3 years ago
4 0
The maximum weight that could be held would be 32 pounds. or six five pound weights taking up 18 inches of space, and weighing 30 Lbs, and two one pound weights adding another two inches. You could achieve a greater weight if you had a weight of one-half inch, in which case you could take six 5 lb weights and 1 two  pound weight, then you could add a half inch weight bringing the weight to over 32 inches. Since we don't have a half inch weight we can't raise the weight above 32lbs.
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g Suppose I will flip a fair coin until it lands Heads for the first time, and you will receive $2 if the game lasts for 1 round
Anuta_ua [19.1K]

Answer:

Step-by-step explanation:

The main idea is that I would like to pay less than what I'm expecting to win, so in that way, I get a profit out of playing this game. Let X be the number of tosses until I get a Heads. By definition, this is a geometric random variable with parameter p = 1/2.

Let Y the amount I received for playing. So, we want to calculate the expected value of Y.

We can calculate it as follows

E[Y] = 2 P(X=1)+ 4 P(X=2)+ 8 P(X =3)  + \dots  = \sum_{n=1}^infty 2^n P(X=n)

Since X is a geometric random variable, we have that P(X=n) = (\frac{1}{2})^{n-1}\frac{1}{2}

Then,

E[Y] = \sum_{n=1}^\infty 2^{n} (\frac{1}{2})^{n-1} \frac{1}{2} = \sum_{n=1}^\infty 2^{n-1} \cdot \frac{1}{2^{n-1}} = \sum_{n=1}^\infty 1 = \infty

So, we expect to have an infinite amount. Given this, we can pay as much as we want to play the game.

5 0
3 years ago
F(x)=sqrt x+2; g(x)=sqrt 8x-6. FInd f(g(x))
zhenek [66]

Hello!

This question is an example of composition of functions. It is using range values of some given function as domain values of some other given function to find new range values. Remember that the domain of the composite function will be the same as the domain of the first function.

Given f(g(x)), for f = \sqrt{x+2}, substitute x with g(x) = \sqrt{8x-6}.

Therefore, f(g(x))= \sqrt{\sqrt{8x-6} +2}.

7 0
3 years ago
Quadrilateral QRST is a rectangle. RT = 5x + 1 and QS = 6x – 3. Find QS.
Kaylis [27]

Answer:

21.

Step-by-step explanation:

RT and QS are diagonals of the rectangle and are equal in length.

5x + 1 = 6x - 3

-x = -4

x = 4

So QS = 6(4) - 3

= 21.

5 0
3 years ago
Read 2 more answers
El angulo de elevacion del sol es de 29°12'35''. Calcular la longitud de la sombra proyectada por un hombre de 1,75m de estatura
Bingel [31]

Respuesta:

3,59 metros

Explicación paso a paso:

Conversión del ángulo de elevación a grados;

29 ° 12 '35 "

= 29 ° + 12 '/ 60 + 35 "/ 3600

= 29,20972 °

Resolviendo el triángulo de solución adjunto:

La longitud de la sombra se puede obtener utilizando la relación trigonométrica;

Sin θ = opuesto / hipoteno

Sin 29.20972 = 1.75 / sombra

Sombra = 1.75 / Sin 29.20972

Longitud de la sombra = 3,59 m

3 0
3 years ago
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igor_vitrenko [27]

Answer:

What does the pyramid look like

Step-by-step explanation:

7 0
3 years ago
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