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stepan [7]
3 years ago
14

If Jonny has 3 apple and take away 1 how many do he have

Mathematics
2 answers:
ELEN [110]3 years ago
6 0

Answer:

2 Two

Step-by-step explanation:

3-1=2 if you take away one from three there will be two

Wewaii [24]3 years ago
5 0
Two / 2 because 1, 2, 3 - 1 = 2
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Through: (1,-1), Parallel to y = 1/4× - 4​
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I believe it is y=1/4x.

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Hat value is needed to fill in the blank to make this trinomial a perfect square trinomial. 4x2 + __x + 81?
Doss [256]
36, because the square root of 4 is 2 and the square root of 81 is 9. You multiply those and then double it to get 36.
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3 years ago
What is the Gcf of 10,20,78
Ksivusya [100]
The answer to this is 2. Ten only has two factors, 5 and 2, and 2 can be decided evenly amongst them all.
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Find an equation of the line passing through the given points (1,-3) and (3,3)
chubhunter [2.5K]

ANSWER: y= 3x - 6

STEP-BY-STEP EXPLANATION:

(1,-3) and (3,3)

X1=1           X2=3

Y1= - 3       Y2=3

1) Find the slope of the line.

To find the slope of the line passing through these two points we need to use the slope  formula:

m = \frac{Y2-Y1}{X2-X1}

m= \frac{3-(-3)}{3-1}   m=\frac{6}{2} = 3

2)Use the slope to find the y-intercept.

Now that we know the slope of the line is 3 we can plug the slope into the equation and  we get:

y= 3x+b

Next choose one of the two point to plug in for the values of x and y. It does not matter  which one of the two points you choose because you should get the same answer in either  case. I generally just choose the first point listed so I don’t have to worry about which  one I should choose.

y= 3x+b       point (1,-3)

-3= 3(1) + b

-3-3=b

-6=b

3)Write the answer.

Using the slope of 3 and the y-intercept of -6 the answer is:

y = 3x - 6

6 0
3 years ago
Assuming that the equations define x and y implicitly as differentiable functions x=f(t),y=g(t) find the slope of the curve x=f(
Mumz [18]
The given equations are
x(t+1)-4t \sqrt{x} =9            (1)
2y+4y^{3/2}=t^{3}+t           (2)

When t=0, obtain
x=9 \\ 2y+4y^{3/2}=0 \,\,=\ \textgreater \ \, y(1+2 \sqrt{y} )=0 \,=\ \textgreater \ \,y=0

Obtain derivatives of (1) and find x'(0).
x' (t+1) + x - 4√x - 4t*[(1/2)*1/√x = 0
x' (t+1) + x - 4√x -27/√x = 0
When t=0, obtain
x'(0) + x(0) - 4√x(0) = 0
x'(0) + 9 - 4*3 = 0
x'(0) = 3
Here, x' means \frac{dx}{dt}.

Obtain the derivative of (2) and find y'(0).
2y' + 4*(3/2)*(√y)*(y') = 3t² + 1
When t=0, obtain
2y'(0) +6√y(0) * y'(0) = 1
2y'(0) = 1 
y'(0) = 1/2.
Here, y' means \frac{dy}{dt}.

Because \frac{dy}{dx} = \frac{dy}{dt} / \frac{dx}{dt}, obtain
\frac{dy}{dx} |_{t=0}\, =  \frac{1/2}{3}= \frac{1}{6}

Answer:
The slope of the curve at t=0 is 1/6.



3 0
3 years ago
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