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3 years ago

what's the probability and the deck of cards have 52 cards what's the probability of picking a black card

Mathematics

2 answers:

Crank3 years ago

8 0

N(S) = 52
n(A) = 2 * 13 = 26 black cards
$P(A) =\frac{n(A)}{n(S)}=\frac{26}{52}=\frac{1}{2}$

olga nikolaevna [1]3 years ago

4 0

There is a 26 percent chance of picking one since there are only 2 colors black and red

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A rose garden can be planted for $4000. The marginal cost of growing a rose is estimated to $0.30,

wariber [46]

Answer:

$C(x)=4000+0.3x$

$R(x)=1.75x$

$Profit= 1.45x-4000$

Step-by-step explanation:

We are given that A rose garden can be planted for $4000.

The marginal cost of growing a rose is estimated to $0.30,

Let x be the number of roses

So, Marginal cost of growing x roses = $0.3x$

Total cost = $4000+0.3x$

So, Cost function : $C(x)=4000+0.3x$ ---A

Now we are given that the total revenue from selling 500 roses is estimated to $875

So, Marginal revenue = $\frac{\text{Total revenue}}{\text{No. of roses}}$

Marginal revenue = $\frac{875}{500}$

Marginal revenue = $1.75$

Marginal revenue for x roses = $1.75x$

So, Revenue function = $R(x)=1.75x$ ----B

Profit = Revenue - Cost

$Profit= 1.75x-4000-0.3x$

$Profit= 1.45x-4000$ ---C

Now Plot A , B and C on Graph

$C(x)=4000+0.3x$ -- Green

$R(x)=1.75x$ -- Purple

$Profit= 1.45x-4000$ --- Black

Refer the attached graph

6 0

2 years ago

A rectangle has vertices at these coordinates.(3,6), (3,4), (6,4)What are the coordinates of the fourth vertex of the rectangle?

omeli [17]

Hi, i hope this helps! The coordinates are (6,6). I figured this out by plotting the given points and remembering that a rectangle has parallel sides and right angles :))

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3 years ago

Amy's grandmother gave her 3 identical chocolate chip cookies and 4 identical sugar cookies. In how many different orders can Am

Dmitrij [34]

Answer:

chocolate chip cookie first: 15 ways

chocolate chip cookie last: 15 ways

chocolate chip cookie first and last: 5 ways

Step-by-step explanation:

There is a total of 7 cookies.

Is she eats a chocolate cookie first, she will have 2 chocolate cookies and 4 sugar cookies (6 in total).

So, to find the number of different orders that Amy can eat the remaining cookies, we just need to calculate a combination of 6 choose 2 (that is, the number of ways we can put the 2 chocolate cookies among the 6 cookies) or a combination of 6 choose 4 (same thing, but for the sugar cookies):

C(6,2) = 6! / (2! * 4!) = 6 * 5 / 2 = 15 ways

Is she eats a chocolate cookie last, she will have 2 chocolate cookies and 4 sugar cookies (6 in total), so the problem is solved again with a combination of 6 choose 2:

C(6,2) = 15 ways

Is she eats a chocolate cookie first and last, she will have just 1 chocolate cookie left and 4 sugar cookies (5 in total), so the problem is solved with a combination of 5 choose 1 or a combination of 5 choose 4:

C(5,1) = 5! / (1! * 4!) = 5 ways

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