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Amanda [17]
3 years ago
6

A factory adds three red drops and two blue drops of coloring to white paint to make each pint purple The factory will make 50 g

allons of purple paint how many drops of red and blue paint to get 50 gallons
Mathematics
1 answer:
Radda [10]3 years ago
7 0

30 gallons of red paint  &  20 gallons of blue paint

Step-by-step explanation:

The ratio of red to blue paint drops to make purple paint is 3 : 2

Therefore the total number of gallon, in this case, fifty (50) is equivalent to the total of two ratios (which is 3 + 2 5)

If 5 in the ratio = 50; what about 2  & 3

5 = 50

2 = x

After cross multiplication;

5x = 50 * 2

X = 100/5

X = 20

The same for ratio 3

5 = 50

3 = y

5y = 50 * 3

y = 150/5

y = 30

The answer is therefore; 30 gallons of red paint to 20 gallons of blue paint

Learn More:

For more on ratios check out;

brainly.com/question/11662922

#LearnWithBrainly

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8 percent

Step-by-step explanation:

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6 0
3 years ago
find all integers x satisfying each of the following congruences mod n. if no such x exists, explain why not
zalisa [80]

Answer:

please find the solution:

Step-by-step explanation:

please find the correct question:

Given value:  

\to 4x \equiv  2(mod\ n) \ \ \ \ \ \ \ \ \ \ \ \ _{where} \ \  n=6\\\\\to  4x \equiv  2 (mod 6)

\to 4x-2 should be divisible by 6  we are also given that 0 \leq x < n  and start with x = 0  

\to 4x-2 =-2 which is not divisible by 6  

x= 1  

\to 4x-2 = 2 not divisilble by 6  

x= 2

\to 4x-2 = 6 which is divisible by 6  

x=3  

\to 4x-2 = 10 not divisible by 6

x=4  

\to 4x-2  = 14 not divisible by 6  

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so such x are x = 2 and x = 5

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gogolik [260]

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5/24

Step-by-step explanation:

Enter a problem...

Algebra Examples

Popular Problems Algebra Write the Fraction in Simplest Form (5/6)÷4

5/6 ÷ 4

Rewrite the division as a fraction.

5/6

4

Multiply the numerator by the reciprocal of the denominator.

5/6

⋅

1/4

Multiply

5/6

⋅

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.

Tap for fewer steps...

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⋅

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Multiply

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by

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The result can be shown in multiple forms.

Exact Form:

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