Answer:
At (-2,0) gradient is -4 ; At (2,0) gradient is 4
Step-by-step explanation:
For this problem, we simply need to take the derivative of the function and evaluate when y = 0 (when crossing the x-axis).
y = x^2 - 4
y' = 2x
The function y = x^2 - 4 cross the x-axis when:
y = x^2 - 4
0 = x^2 - 4
4 = x^2
2 +/- = x
Hence, this curve crosses the x-axis twice, once at (-2,0) and again at (2,0).
The gradient at these points are as follows:
y' = 2(-2) = -4
y' = 2(2) = 4
Cheers.
I’m pretty sure it’s the first one cause it’s half of the 6 blocks
2 2/3 = 2x3+2/3 = 8/3
8/3 / 1/3 = 8/3 x 3/1 = 8/1 = 8
Answer:
2/1
Step-by-step explanation:
Answer:
23
Step-by-step explanation:
supplementary angles: 180-85 = 95
95 = 5x-20 ( i forgot the name of the rule, something relating to same side interior angles i think)
115 = 5x
23= x
hope that helped
