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dalvyx [7]
3 years ago
11

A square pyramid is sliced parallel to the base, as shown. What is the area of the resulting two-dimensional cross-section? Squa

re pyramid intersected horizontally by a rectangle. The base of the pyramid measures 10 feet by 10 feet, and the height is 12 feet. The part of the rectangle that intersects the pyramid is a gray square. The square measures 4 feet by 4 feet. A.16 ft² B.40 ft² C.48 ft² D.120 ft²

Mathematics
2 answers:
DiKsa [7]3 years ago
5 0
The answer is D. 

Hope this helps!

If it doesn't, let me know.
creativ13 [48]3 years ago
5 0

Answer:

Option A is correct.

Step-by-step explanation:

Given a square pyramid is sliced parallel to the base, we have to find the area of the resulting two-dimensional cross-section.

Square pyramid intersected horizontally by a rectangle. The base of the pyramid measures 10 feet by 10 feet, and the height is 12 feet. The part of the rectangle that intersects the pyramid is a gray square. The square measures 4 feet by 4 feet.

Now, we have to find the area of the resulting two-dimensional cross-section i.e of grey square whose dimensions are 4 feet by 4 feet.

\text{Area of cross-section=}side\times side=4\times 4=16 ft^2

Hence, area of resultant cross-section is 16 square feet.

Option A is correct.

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Step-by-step explanation:

In this question we need to decrease 216 by 37\dfrac{1}{2}\% or 37.5 %.

For this, firstly find 37.5 % of 216.

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Now subtracting 81 from 216 to find decrease of 216 by 37.5 %.

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