Answer: The z-scores for a woman 6 feet tall is 2.96 and the z-scores for a a man 5'10" tall is 0.25.
Step-by-step explanation:
Let x and y area the random variable that represents the heights of women and men.
Given : The heights of women aged 20 to 29 are approximately Normal with mean 64 inches and standard deviation 2.7 inches.
i.e.

Since , 
Then, z-score corresponds to a woman 6 feet tall (i.e. x=72 inches).
[∵ 1 foot = 12 inches , 6 feet = 6(12)=72 inches]

Men the same age have mean height 69.3 inches with standard deviation 2.8 inches.
i.e.

Then, z-score corresponds to a man 5'10" tall (i.e. y =70 inches).
[∵ 1 foot = 12 inches , 5 feet 10 inches= 5(12)+10=70 inches]

∴ The z-scores for a woman 6 feet tall is 2.96 and the z-scores for a a man 5'10" tall is 0.25.
Since it’s a 90° angle if u draw it on a grid with the given units C would be 5 until a when measured
Answer:
download a app called photo math
Step-by-step explanation:
Thank me later
6-8x=-3x+11
-8x+3x=11-6
-5x=5
x=-1
The first step is to isolate the variable, then you solve. Hope this helps, brainliest if you can.
The solutions to q² - 125 = 0 are q = ±√125.
q = -5√5
q = 5√5