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Lapatulllka [165]
2 years ago
7

Which fraction is equivalent to 4 over negative 9?

Mathematics
2 answers:
Neporo4naja [7]2 years ago
7 0
A is correct.  Just move the negative sign from in front of the 9 and place it in front of the 4.
Crank2 years ago
7 0

Answer:

A) -4 over 9

Step-by-step explanation:

We have the fraction \frac{4}{-9} the equivalent of this fraction is \frac{-4}{9}

\frac{4}{-9}= \frac{-4}{9} =-\frac{4}{9}

Both fractions are the same and equivalent, the negative sign makes the whole fraction negative regardless of whether it is in the numerator or denominator.

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The function g(x) = 8x2 – 48x + 65 written in vertex form is g(x) = 8(x – 3)2 – 7. What is the vertex of g(x)?
maksim [4K]
The answer is (3, -7). If the function is written in the form y = a(x – h)^2 + k, the vertex will be (h, k). Let's write the function 8x^2 – 48x + 65 in the form of a(x – h)^2 + k. g(x) = 8x^2 – 48x + 65. g(x) = 8x^2 – 48x + 72 - 72 + 65. g(x) = (8x^2 – 48x + 72) - 7. g(x) = (8 * x^2 – 8 * 6x + 8 * 9) - 7. g(x) = 8(x^2 - 6x + 9) - 7. g(x) = 8(x - 3)^2 - 7. The function is now in the form a(x – h)^2 + k, where a = 8, h = 3, and k = -7. Thus, the vertex is (3, -7).
4 0
3 years ago
Read 2 more answers
Trong một lớp học có $35$ sinh viên nói được tiếng Anh, $25$ sinh viên nói được tiếng Nhật trong đó có $10$ sinh viên nói được c
Reil [10]

Answer:

please write this question in English then I give answer

8 0
2 years ago
Sea un cuadrado de 2 pulgadas de lado uniendo los puntos medios se obtiene otro cuadrado inscrito en el anterior si repetimos es
Ne4ueva [31]

Answer:

1) La serie geométrica formada es

4, 2, 1,..., ∞

2) La suma al infinito de las áreas de los cuadrados es 8 in.²

Step-by-step explanation:

1) El área del primer cuadrado, a₁ = 2² = 4 pulgadas²

El área del siguiente cuadrado, a₂ = (√ (1² + 1²)) ² = (√2) ² = 2 pulg²

El área del siguiente cuadrado, a₃ = ((√ (2) / 2) ² + (√ (2) / 2) ²) = 1 pulg²

Por lo tanto, la razón común, r = a₂ / a₁ = 2/4 = a₃ / a₂ = 1/2

Las áreas de los cuadrados progresivos forman una progresión geométrica como sigue;

4, 4×(1/2), 4 ×(1/2)²,...,4×(1/2)^{\infty}

De donde obtenemos la serie geométrica formada de la siguiente manera;

4, 2, 1,..., ∞

2) La suma de 'n' términos de una progresión geométrica hasta el infinito para -1 <r <1 se da como sigue;

S_{\infty} = \dfrac{a}{1 - r}

Por lo tanto, la suma de las áreas de los cuadrados hasta el infinito se obtiene sustituyendo los valores de 'a' y 'r' en la ecuación anterior de la siguiente manera;

La \ suma \ al \ infinito \ del \ cuadrado \ S_{\infty}  = \dfrac{4 \ in.^2}{1 - \dfrac{1}{2} } = \dfrac{4 \ in.^2}{\left(\dfrac{1}{2} \right)} = 2 \times 4 \ in.^2= 8 \ in.^2

La suma al infinito de las áreas de los cuadrados, S_{\infty} = 8 in.²

7 0
2 years ago
The drawing below shows circle B and circle E.Which equation best describes the relationship between BC and EF?
Svet_ta [14]

Answer:

BC = 3(EF)

Step-by-step explanation:

The question stated that AC is 3 times the length of DF.

7 0
2 years ago
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Compare and contrast multiplication and division with 0 and1
ankoles [38]
Anything times 0  is 0
anything times 1 is the number the was multiplied <span />
6 0
3 years ago
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