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2 years ago

Beinggreat78, Answer fast!

Mathematics

2 answers:

sammy [17]2 years ago

7 0

Answer:

$I~am~here!!!$

C. ⇒ 2 : 4. This is because 2 may be a multiple of 1, however, 3 is not a direct multiple of 4.

hichkok12 [17]2 years ago

4 0

C. Because is 1:3 started with a 2 it would have to be 2:6 and 1:3 can not convert into 2:4

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Choose two positive integers a and b, making sure that a<5 and b>80 . The width of a rectangular computer screen is a inch

qwelly [4]

Answer:

Dimensions of the screen are a minimum of 10 inches wide by 8 inches high. The difference between the height and width will be 2 inches

Step-by-step explanation:

$Height = H$

$Width = H + a$

$Area = Height x Width$

$b = H * (H + a)$

$b = H^{2} + aH$

$H^{2} + aH > 80$

$H^{2} + aH - 80 > 0$

a<5 means 'a' can be a = 1, 2, 3, 4

Solving for H for each option of 'a' will give values of 'H' using the quadratic formula below

$H = \frac{-b\±\sqrt{b^{2}-4ac}}{2a}$

As 'a' and 'b' must be positive integers, H and W must be positive integers as well,

$a = 1, H = 8.46, H = -9.46$

$a = 2, H = 8, H = -10$

$a = 3, H = 7.57, H = -10.57$

$a = 4, H = 7.17, H = -11.17$

Based on above possible answers:

$a=2, H=8$

$W = H + a$

$W = 8 + 2$

$W = 10$

Dimensions of the screen are a minimum of 10 inches wide by 8 inches high. The difference between the height and width will be 2 inches

5 0

3 years ago

5. Area = 36cm<br>HM = 12 cm<br>OE = x

Tpy6a [65]

Answer:

I'm going to guess and say that if HM is one side and OE is the other side of a rectangle, then:

OE = 3 cm

Step-by-step explanation:

36/12 = 3 cm

7 0

2 years ago

Read 2 more answers

What is the Volume of the square pyramid? (Round to the nearest tenth as needed)

goldenfox [79]

Answer:

5229 mm³

Step-by-step explanation:

Volume of square pyramid

$\sf \boxed{Volume \ of \ the \ square \ pyramid = \dfrac{1}{3}*b^2*H}$

b = base length = 25 mm

H = height

We have to find 'H' using Pythagorean theorem,

slant height (hypotenuse) = 28 mm

leg₁ = base length ÷ 2 = 25÷2 = 12.5

leg₂ = H

H² + (12.5)² = 28²

H² = 784 - 156.25

= 627.75

$\sf H = \sqrt{627.75}$

H = 25.01 mm

$\sf \text{Volume of square pyramid =$\dfrac{1}{3}*25*25*25.1$ }$

= 5229 mm³

$\sf \boxed{\text{Volume of square pyramid = \dfrac{1}{3}*25*25*28}}$

3 0

1 year ago

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Find the slope of the line passing through the points (8,-3) and (4,-1)

docker41 [41]

$\rm \to m = \dfrac{y_2 - y_1}{x_2 - x_1}$

$\\ \\$

$\rm \to m = \dfrac{ - 1 - 3}{4 - 8}$

$\\ \\$

$\rm \to m = \dfrac{ - 4}{4 - 8}$

$\\ \\$

$\rm \to m = \dfrac{ - 4}{ - 4}$

$\\ \\$

$\rm \to m = \cancel \dfrac{ - 4}{ - 4}$

$\\ \\$

$\rm \to m = 1$

7 0

2 years ago

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A group of college students built a self-guided rover and tested it on a plane surface. They programmed the vehicle to move alon

makkiz [27]

Answer:

B. 40 meters

Step-by-step explanation:

— Estimating

The rectangle enclosing the path has sides of length 9 m and 14 m, so its perimeter is 2(9+14) = 46 m. The distance covered will be shorter than that.

The distance from A to C is longer than the distance from D to C, so we know the distance will be longer than 2·14+9 = 37 m.

Only one answer choice fits in the range 37 < d < 46.

____

— Detailed calculation

The distance from B to C is the hypotenuse of a right triangle with sides 9 and 12. You will recognize that these side lengths are 3 times the side lengths of a 3-4-5 right triangle, so the hypotenuse distance is 3·5 = 15 meters.

The circuit length is ...

AB +BC +CD +DA = 2 + 15 + 14 + 9 = 40 . . . . meters

4 0

3 years ago