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BabaBlast [244]
3 years ago
14

Drag and drop each expression into the box to correctly classify it as having a positive or negative product

Mathematics
1 answer:
AfilCa [17]3 years ago
5 0

Following expressions will have negative product

(\frac{1}{2})(-\frac{1}{2})\ and\ (-\frac{1}{2})(\frac{1}{2})

Following expressions will have positive product

(-\frac{1}{2})(-\frac{1}{2})\ and\ (\frac{1}{2})(\frac{1}{2})

Further explanation:

We will see at each expression one by one

First expression is:

(-\frac{1}{2})(\frac{1}{2})

In the given expression one term is positive and one term is negative. The product of negative and positive terms is negative.

Second Expression is:

(-\frac{1}{2})(-\frac{1}{2})

Both terms are negative and the product of two negative terms is positive.

Third Expression is:

(\frac{1}{2})(-\frac{1}{2})

The expression has one positive and one negative term so the product will be negative

Fourth Expression is:

(\frac{1}{2})(\frac{1}{2})

Both terms are positive so the product will also be positive

Keywords: Product, Expressions

Learn more about expressions at:

  • brainly.com/question/10699220
  • brainly.com/question/10703930

#LearnwithBrainly

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I was never sure of what the "additive inverse" is. 
So, just now, just for you, I went and looked it up.

The additive inverse of any number ' A ' is the number
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So now, let's check out the choices:

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That second number, -(-6), is the same as +6 .
So the two numbers are the same.
Do you get zero when you add them up ?  No.

b). -7, 7
What do you get when you add -7 and 7 ?
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c). -7, -7
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You get zero.
So these ARE additive inverses.

What do we end up with from the list of choices:

a).,  c).,  and d). are NOT additive inverses.

b). and e). ARE additive inverses.

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