Prove that if m + n and n + p are even integers, where m, n, and p are integers, then m + p is even.
m=2k-n, p=2l-n
Let m+n and n+p be even integers, thus m+n=2k and n+p=2l by definition of even
m+p= 2k-n + 2l-n substitution
= 2k+2l-2n
=2 (k+l-n)
=2x, where x=k+l-n ∈Z (integers)
Hence, m+p is even by direct proof.
What's the question she got the answer wrong to?
Answer:
-3/4
Step-by-step explanation:
To find the slope, plug the coordinates into the slope formula.
y2 - y1 / x2 - x1
4 - (-2) / -7 - 1
6 / - 8
-3/4
You can't simplify this equation anymore.
