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Sav [38]
3 years ago
12

I NEED HELP ASAP. PLZ HELP

Mathematics
1 answer:
AleksAgata [21]3 years ago
5 0

Answer:

Y=x+1...written on the line between c and b

Step-by-step explanation:

CB is perpendicular to EF.

The slope is 1, the y intercept is 1

Therefore. Y =mx+B is y=1x+1

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Find sin theta if cos theta is 4/5
Dima020 [189]

Answer:

Step-by-step explanation:

hello :

cos²θ +sin²θ = 1 and cosθ =4/5

(4/5)² + sin²θ = 1 so : sin²θ = 1 - 16/25

sin²θ = 9/25 = (3/5)²

sinθ = 3/5 or sinθ = - 3/5 because : (3/5)²= (- 3/5)²= 9/25

5 0
3 years ago
Help meeeeeee please :))))
maxonik [38]
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6 0
3 years ago
What is the image point of (2,4) after a translation left 4 units and down 1 unit? hat is the image point of (0,1) after a trans
denis-greek [22]

Want me to help

Step-by-step explanation:

5 0
3 years ago
Read 2 more answers
Solve the equation for the variable numerically using a
tangare [24]

Answer:

x= 12

Step-by-step explanation

3x+8=44

subtract 8 from both sides:  3x+8= 44

                                                     -8    -8

3x=36

then divide by 3 on both sides

3x=36

3    3

which leaves : x=12

my explaining is horrible but i hope this helps

8 0
3 years ago
The following table shows the distance from school as a function time
kykrilka [37]

Answer:

27,0 the distance away from the school​

Step-by-step explanation:

Apply the formula for equation of a straight line;

y=mx+c where c is the y intercept , and m is the gradient

From the graph, the slope is negative where speed decreases with increase in time

Find the gradient by applying the formula;

m=\frac{y_2-y_1}{x_2-x_1}

Taking y₁=24, y₂=20, x₁=9, x₂=12

Then;

m=\frac{20-24}{12-9} =\frac{-4}{3}

write the equation of the function as ;

y=mx+c, c=36( the y-intercept when x=0) hence the equation is;

y=mx+c\\\\y=\frac{-4}{3}x+36

To get x-intercept, substitute value of y with 0

y=mx+c\\\\\\y=-\frac{4}{3} +36\\\\\\0=-\frac{4}{3} x+36\\\\\frac{4}{3}x =36\\\\\\4x=36*3\\\\\\x=108/4=27

This means that the x-intercept is 27 ,and this means you will require 27 minutes to cover the whole distance to the school.

4 0
4 years ago
Read 2 more answers
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