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xz_007 [3.2K]
3 years ago
6

In the equation, 4x+14=-2x-22+12 , what are some of the steps that should be taken to solve for x? Select all that apply.

Mathematics
1 answer:
AlexFokin [52]3 years ago
5 0
'A' and 'C' are very helpful. 'B' and 'D' won't do you any good.
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The surface area of the solid is about ____ inches squared
Dafna11 [192]

Answer:

Surface area of the whole figure=  320.28inch^2

Step-by-step explanation:

The surface area of the figure :

Surface area of the cylinder(excluding top)+Surface area of the cone(excluding bottom)

Radius of the cylinder=3 inch     and  Height of cylinder=13 inch

Surface area of the cylinder with one circular face

                                    =2\pi rh+\pi r^2

As,     \pi =\frac{22}{7}= 3.14

   =(2*3.14*3*13)+(3.14*3*3)\\\\=244.92+28.26\\\\=273.18inch^2

Surface area of the cone excluding  base:

                =\pi *r*l

l= slant height=5 inch       r= radius= 3 inch

Surface area of the cone =3.14*3*5

                                        =47.1inch^2

Total surface area of the whole figure=273.18+47.1

                                                           =  320.28inch^2

5 0
3 years ago
Six - two times twelve plus five
fomenos

Answer:

Ok, so the equation would be 6-2*12+5. The answer to that is -13.

Step-by-Step Explanation:

You would use PEMDAS. First, you multiply 2 and 12 and that's 24. Now your equation is 6-24+5. Then you subtract 6 and 24 and that's -18. Now your equation is -18+5, and the answer to that equation is -13. I hope this helps you!!

6 0
2 years ago
Please help me out :P
Veseljchak [2.6K]

cos θ = \frac{-4\sqrt{65} }{65}, sin θ = \frac{-7\sqrt{65} }{65}, cot  θ  = 4/7, sec  θ = \frac{-\sqrt{65} }{4}, cosec  θ  = \frac{-\sqrt{65} }{7}

<h3>What are trigonometric ratios?</h3>

Trigonometric Ratios are values of all the trigonometric functions based on the value of the ratio of sides in a right-angled triangle.

Sin θ: Opposite Side to θ/Hypotenuse

Tan θ: Opposite Side/Adjacent Side & Sin θ/Cos

Cos θ: Adjacent Side to θ/Hypotenuse

Sec θ: Hypotenuse/Adjacent Side & 1/cos θ

Analysis:

tan θ = opposite/adjacent = 7/4

opposite = 7, adjacent = 4.

we now look for the hypotenuse of the right angled triangle

hypotenuse = \sqrt{7^{2} + 4^{2} } = \sqrt{49+16} = \sqrt{65}

sin θ = opposite/ hyp = \frac{7}{\sqrt{65} }

Rationalize, \frac{7}{\sqrt{65} } x \frac{\sqrt{65} }{\sqrt{65} } = \frac{7\sqrt{65} }{65}

But θ is in the third quadrant(180 - 270) and in the third quadrant only tan and cot are positive others are negative.

Therefore, sin θ = - \frac{7\sqrt{65} }{65}

cos   θ  = adj/hyp = \frac{4}{\sqrt{65} }

By rationalizing and knowing that cos  θ  is negative, cos θ  = -\frac{-4\sqrt{65} }{65}

cot θ  = 1/tan θ  = 1/7/4 = 4/7

sec θ  = 1/cos θ  = 1/\frac{4}{\sqrt{65} } = -\frac{-\sqrt{65} }{4}

cosec θ  = 1/sin θ  = 1/\frac{\sqrt{65} }{7} = \frac{-\sqrt{65} }{7}

Learn more about trigonometric ratios: brainly.com/question/24349828

#SPJ1

5 0
1 year ago
What is 78 divided by 3is in long sovision
Xelga [282]
    26
3<span>⟌78
   -6
-------
    18
   -18
-------
      0

</span>
6 0
3 years ago
Please help.........
Romashka-Z-Leto [24]
What you need help with
8 0
3 years ago
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