5^3 Sartre 10 + 4^3 sqrt 10
To solve this problem, we can use the tan function to find
for the distances covered.
tan θ = o / a
Where,
θ = angle = 90° - angle of depression
o = side opposite to the angle = distance of boat from
lighthouse
a = side adjacent to the angle = height of lighthouse = 200
ft
When the angle of depression is 16°18', the initial distance
from the lighthouse is:
o = 200 tan (90° - 16°18')
o = 683.95 ft
When the angle of depression is 48°51', the final distance
from the lighthouse is:
o = 200 tan (90° - 48°51')
o = 174.78 ft
Therefore the total distance the boat travelled is:
d = 683.95 ft - 174.78 ft
<span>d = 509.17
ft</span>
Answer:
C. ![f(x)=\sqrt[3]{-x} -1](https://tex.z-dn.net/?f=f%28x%29%3D%5Csqrt%5B3%5D%7B-x%7D%20-1)
Step-by-step explanation:
Consider graph of the parent function (red curve in attached diagram)
![g(x)=\sqrt[3]{x}](https://tex.z-dn.net/?f=g%28x%29%3D%5Csqrt%5B3%5D%7Bx%7D)
First, multiply it by -1 to get function
![h(x)=-\sqrt[3]{x}](https://tex.z-dn.net/?f=h%28x%29%3D-%5Csqrt%5B3%5D%7Bx%7D)
Then translate the graph of the function h(x) 1 unit down, then you'll get the function
![f(x)=-\sqrt[3]{x} -1\\ \\ \text{or}\\ \\f(x)=\sqrt[3]{-x} -1](https://tex.z-dn.net/?f=f%28x%29%3D-%5Csqrt%5B3%5D%7Bx%7D%20-1%5C%5C%20%5C%5C%20%5Ctext%7Bor%7D%5C%5C%20%5C%5Cf%28x%29%3D%5Csqrt%5B3%5D%7B-x%7D%20-1)
The graph of the function f(x) is represented by the blue curve in attached diagram
We normally think of 3x7, but the "7" is one more than 2 widths ... double the 3 and halve the 7 ==> 6 by 3.5 works ...
