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Veronika [31]
3 years ago
13

Bethany sells roses and petunias. The expression 3r+2.5p gives the cost (in dollars) of r roses and pp petunias. What is the cos

t of 7 roses and 8 petunias?\$
Mathematics
1 answer:
a_sh-v [17]3 years ago
7 0
(3×7)+(2.5×8)=(21)+(20)=$41
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Answer:

first, make a dot on (0,-1)

Then, you draw a line that is -1/2

The way you draw a line explaination:

for every x, you go down and left by half a box.

for example, the next dot is (-1, -1.5)or (-1, -1/2)

and the next point after that is (-2, -1) and so on...

reminder: it goes on forever on both sides!

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2 years ago
I need help i don’t understand
UNO [17]

9514 1404 393

Answer:

  x = 12.5

Step-by-step explanation:

The value of x is part of the value of an angle in a triangle where the other angles are known. This suggests that the relevant theorem is the "angle sum theorem," which tells you <em>the sum of angles in a triangle is 180°</em>.

This gives you the equation ...

  60° +60° +(4x+10°) = 180° . . . . total of all angles is 180°

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2 years ago
Los numeros primos menores que 15​
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Answer:

2, 3, 5, 7, 11, 13,

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3 years ago
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Hi! please help i’ll give brainliest
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Third option: Rocks being broken apart

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Eighteen telephones have just been received at an authorized service center. Six of these telephones are cellular, six are cordl
Karo-lina-s [1.5K]

Full Question

Eighteen telephones have just been received at an authorized service center. Six of these telephones are cellular, six are cordless, and the other six are corded phones. Suppose that these components are randomly allocated the numbers 1, 2, . . . , 18 to establish the order in which they will be serviced.

What is the probability that after servicing twelve of these phones, phones of only two of the three types remain to be serviced?

What is the probability that two phones of each type are among the first six serviced?

Answer:

a. 0.149

b. 0.182

Step-by-step explanation:

Given

Number of telephone= 18

Number of cellular= 6

Number of cordless = 6

Number of corded = 6

a.

There are 18C6 ways of choosing 6 phones

18C6 = 18564

From the Question, there are 3 types of telephone (cordless, Corded and cellular)

There are 3C2 ways of choosing 2 out of 3 types of television

3C2 = 3

There are 12C6 ways of choosing last 6 phones from just 2 types (2 types = 6 + 6 = 12)

12C6 = 924

There are 2 * 6C6 * 6C0 ways of choosing none from any of these two types of phones

2 * 6C6 * 6C0 = 2 * 1 * 1 = 2.

So, the probability that after servicing twelve of these phones, phones of only two of the three types remain to be serviced is

3 * (924 - 2) / 18564

= 3 * 922/18564

= 2766/18564

= 0.149

b)

There are 6C2 * 6C2 * 6C2 ways of choosing 2 cellular, 2 cordless, 2 corded phones

= (6C2)³

= 3375

So, the probability that two phones of each type are among the first six serviced is

= 3375/18564

= 0.182

5 0
3 years ago
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