I hope this helps you
Let G be a group with |G|=pk, where p is a prime and k≥1. Show that has a normal sub group of order for all 1 ≤ m ≤ k.
1 answer:
You might be interested in
The given equation is in point-slope form.
The general form of an equation in point slope form is:
Here m is the slope and
and 
are the coordinates of the point.
So in given equation the slope is 2/3, and the coordinates of point are (1,3)
The general form of an equation in point slope form is:
Here m is the slope and
So in given equation the slope is 2/3, and the coordinates of point are (1,3)
Answer:
The difference is -2
