3 years ago

PLS HELP SHOW ALL YOUR WORKING

Mathematics

1 answer:

Zarrin [17]3 years ago

7 0

A - rolling exactly one six

$P(A)=\dfrac{1}{5}\cdot\dfrac{4}{5}+\dfrac{4}{5}\cdot\dfrac{1}{5}=\dfrac{4}{25}\cdot \dfrac{4}{25}=\dfrac{16}{625}$

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3) INITII equation y=-x+ 4 equation W10 slope (m) = _ y-intercept =

vodomira [7]

Answer:

slope (m) = 1 and intercept = -4

Step-by-step explanation:

comparing with Y = mX - c

4 0

3 years ago

Solve for x. x3=−1000 Enter your answer in the box. x =

levacccp [35]

X³ = -1000

x = ∛-1000

x = -10

In short, Your Answer would be: -10

Hope this helps!

7 0

3 years ago

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BRAINLIEST AND 50 PTS!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!HURRY!!!!!!!!!!!!!

Lana71 [14]

Answer:

Step-by-step explanation

$(8 * 10) + ( 2 * \frac{1}{100} ) + ( 9 * \frac{1}{1000} )$

⇒ 80 + ( 2 * 0.01 ) + ( 9 * 0.001 )

⇒ 80 + 0.02 + 0.009

= 80.029

6 0

3 years ago

Consider the equation below.

Korvikt [17]

Answer:

Equation in square form:

$y=3(x+5)^2-4$

Extreme value:

$(h,k)=(-5,-4)$

Step-by-step explanation:

We are given

$y=3x^2+30x+71$

we can complete square

$y=3(x^2+10x)+71$

we can use formula

$a^2+2ab+b^2=(a+b)^2$

$y=3(x^2+2\times x\times 5)+71$

now, we can add and subtract 5^2

$y=3(x^2+2\times x\times 5+5^2-5^2)+71$

$y=3(x^2+2\times x\times 5+5^2)-3\times 5^2+71$

$y=3(x+5)^2-75+71$

So, we get equation as

$y=3(x+5)^2-4$

Extreme values:

we know that this parabola

and vertex of parabola always at extreme values

so, we can compare it with

$y=a(x-h)^2+k$

where

vertex=(h,k)

now, we can compare and find h and k

$y=3(x+5)^2-4$

we get

h=-5

k=-4

so, extreme value of this equation is

$(h,k)=(-5,-4)$

6 0

3 years ago

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The standard form of the equation of a parabola is y=1/2x^2 - 4x+21. What is the vertex form of the equation?

BartSMP [9]

Answer:

y=1/2*(x-4)^2+13

Step-by-step explanation:

5 0

3 years ago

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