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3 years ago

11

Bethany and her brother ben decided to go through a corn maze. Bethany starts and walks 10 feet north, 30 feet west and then 20

feet north. Ben walks 20 feet North, 25 feet east, and then 15 Feet south. How far apart are Bethany and Ben when they stop walking?

1 answer:

Westkost [7]3 years ago

3 0

Answer:

About 60.77 feet

Step-by-step explanation:

Attached pic.

Blue line is of Bethany

Green line is of Ben

Red line is the distance between them [what we are trying to find]

We can use pythagorean theorem that tells us:

$c^2=a^2+b^2$

Where c is the hypotenuse of the right triangle [red lines in both respective triangles]

and

a, b are the two other sides of the triangle

Left Triangle (using pythagorean theorem):

Base is 30

Left side is 20 - 10 = 10

So,

$c^2=30^2+10^2\\c=\sqrt{30^2+10^2} \\c=31.62$

Right Triangle (using pythagorean theorem):

$c^2=25^2 + 15^2\\c=\sqrt{25^2 + 15^2} \\c=29.15$

Distance between Bethany and Ben = 31.62 + 29.15 = 60.77 feet

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