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Sonbull [250]
3 years ago
14

How do I do these problems?

Mathematics
1 answer:
zaharov [31]3 years ago
6 0
So, We Have Two Problems To Solve:

(-3)÷((-1/3) ÷ (8-4)) ÷ (-12/5)
And
(-1/3)*2÷(7/3 * (-1))÷(-6/5)

So, Lets Do The First One:

We Know That We Need To Use Order Of Operations.
We Need To First Do:
8-4. 
8 - 4 = 4.
So, We Have Now:

<span>(-3)÷((-1/3) ÷ 4) ÷ (-12/5)
</span>So, We Need To Now Convert 4 To An Improper Fraction.
This Becomes 4/1.
Now, We Can Divide (-1/3) By 4.
Dividing Is The Same As Multiplying By The Reciprocal. 
So:
-1     1     -1
--- * --- = ---
 3     4     12
So, We Now Have:

<span>(-3)÷ (-1/12) ÷ (-12/5)
</span>So:
 3    12    36
--- * --- = ---  = -36
 1    -1    -1
So, We Now Have:

<span>-36 ÷ (-12/5)

So:
-36     -5     -180
----- * ----  = ------
  1      12       12

So, We Now Only Have Left to Divide:
-180 </span><span>÷ 12 = -15.
</span>
<span>So, The Value Of The First Question Is -15.
</span>
Now For Number Two:


<span>(-1/3)*2÷(7/3 * (-1))÷(-6/5)
</span>
So, We Use Order Of Operations. 

7/3 * (-1) = -7/3

Next:

<span>(-1/3)*2÷(-7/3)÷(-6/5)
</span>
Now, We Must Do:

-1/3 * 2.
(-1/3) * 2 = (-2/3)
So, Now We Have:

<span>(-2/3) ÷ (-7/3) ÷ (-6/5)

</span>Now, Begin Division.
-2      3     -6         6
---  * --- = ---- =   ----
 3     -7    -21       21
So:
<span>6/21 ÷(-6/5)
</span>
Do The Final Division:

 6      5       30
--- *  ---   = ---- 
21    -6     -126

Simplify:

  30  ÷ 6      5
------    =    -----
-126 ÷ 6    -21

So, Number Two Has A Value Of 5/-21.
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4. Lydia cut out her initial from a piece<br><br> of construction paper,
Ratling [72]

Answer:

Option A is correct.

10 square centimeters.

Step-by-step explanation:

Complete Question

The complete Question is attached in the first attached image.

Lydia cut out her initial from a piece of construction paper. How many square centimeters of construction paper are used to make Lydia's initial?

A) 10 square centimeters

B) 11 square centimeters

C) 15 square centimeters

D) 22 square centimeters

Solution

From the second attached image, it is evident that we can split the L-shaped figure into two rectangles of dimensions (3 cm by 1 cm) and (7 cm by 1 cm)

The total area of the figure is thus

(3 × 1) + (7 × 1) = 10 cm²

Hope this Helps!!!

3 0
4 years ago
Solve y = x + 8 for x.<br> x = y + 8<br> x = y - 8<br> X = -y + 8<br> X = -V +8
JulijaS [17]

Answer:

y = x + 8

Step-by-step explanation:

7 0
3 years ago
Determine whether the statements are True or False. Justify your answer with an explanation.
frez [133]

Problem 1

<h3>Answer: False</h3>

---------------------------------

Explanation:

The notation (f o g)(x) means f( g(x) ). Here g(x) is the inner function.

So,

f(x) = x+1

f( g(x) ) = g(x) + 1 .... replace every x with g(x)

f( g(x) ) = 6x+1 ... plug in g(x) = 6x

(f o g)(x) = 6x+1

Now let's flip things around

g(x) = 6x

g( f(x) ) = 6*( f(x) ) .... replace every x with f(x)

g( f(x) ) = 6(x+1) .... plug in f(x) = x+1

g( f(x) ) = 6x+6

(g o f)(x) = 6x+6

This shows that (f o g)(x) = (g o f)(x)  is a false equation for the given f(x) and g(x) functions.

===============================================

Problem 2

<h3>Answer: True</h3>

---------------------------------

Explanation:

Let's say that g(x) produced a number that wasn't in the domain of f(x). This would mean that f( g(x) ) would be undefined.

For example, let

f(x) = 1/(x+2)

g(x) = -2

The g(x) function will always produce the output -2 regardless of what the input x is. Feeding that -2 output into f(x) leads to 1/(x+2) = 1/(-2+2) = 1/0 which is undefined.

So it's important that the outputs of g(x) line up with the domain of f(x). Outputs of g(x) must be valid inputs of f(x).

7 0
3 years ago
Given the graph of a function f. Identify the function by name. Then Graph, state domain &amp; range in set notation:A) f(x) +2B
WARRIOR [948]

The function in the graph has the name of square function.

The domain of a function is all values of x the function can have. The domain of this function is all real numbers:

\mleft\lbrace x\in\R\mright\rbrace

The range of a function is all values of y the function can have. The range of this function is all positive numbers, including zero:

\mleft\lbrace y\in\R\mright|y\ge0\}

In order to graph f(x) + 2, we just need to translate the graph 2 units up. To find the new points, we need to increase all y-coordinates by 2:

(-2, 6), (-1, 3), (0, 2), (1, 3), (2, 6)

Domain: {x ∈ ℝ}

Range: {y ∈ ℝ | y ≥ 2}

Then, in order to graph f(x) - 2, we just need to translate the graph 2 units down. To find the new points, we need to decrease all y-coordinates by 2:

(-2, 2), (-1, -1), (0, -2), (1, -1), (2, 2)

Domain: {x ∈ ℝ}

Range: {y ∈ ℝ | y ≥ -2}

4 0
1 year ago
Miranda enlarged a picture twice as shown below, each time using a scale factor of 3.
lyudmila [28]

Answer:

The area of the second enlargement is 1,944 square inches

The area of the second enlargement is (3 squared) squared times the original area.

The ratio of the area of the first enlargement to the area of the original equals the square of the scale factor

Step-by-step explanation:

<u><em>Verify each statement</em></u>

1) The area of the first enlargement is 72 square inches.

The statement is false

Because

we know that

The original dimensions of the rectangle are

length 6 inches and width 4 inches

so

First enlargement

Multiply the original dimensions by a scale factor of 3

Length: 6(3)=18\ inches\\Width: 4(3)=12\ inches

The area of the first enlargement is

18(12)=216\ in^2

2) The area of the second enlargement is 1,944 square inches

The statement is true

Multiply the dimensions of the first enlargement by a scale factor of 3

Length: 18(3)=54\ inches\\Width: 12(3)=36\ inches

The area of the second enlargement is

54(36)=1,944\ in^2

3) The area of the second enlargement is (3 squared) squared times the original area.

The statement is true

Because

The original area is 24 square inches

[(3^2)]^2(24)=1,944\ in^2

4) The area of the second enlargement is 3 times the area of the first enlargement

The statement is false

Because

3(216)=648\ in^2

so

648\ in^2 \neq 1,944\ in^2

5) The ratio of the area of the first enlargement to the area of the original equals the square of the scale factor

The statement is true

Because

The square of the scale factor is 3^2=9

and the ratio is equal to

\frac{216}{24}=9

8 0
3 years ago
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