Answer:
B. (4x+5)(16x2−20x+25)
Step-by-step explanation:
64x3+125
=(4x+5)(16x2−20x+25)
Answer:
|F net| = 20.22 N
θ ≈ 19.8°
Step-by-step explanation:
F net = 15N i + 8cos(60°)N i + 8sin(60°)N j
= 15N i + 8×½N i + 8×√3/2N j
= 15N i + 4N i + 4√3N j
= 19N i + 4√3N j
|F net| = √(19²+(4√3)²) = √(361+48) = √409 ≈ 20.22N
tan(θ) = 4√3 ÷ 19 ≈ 0.36 → θ ≈ arctan(0.36) = 19.8°
Answer:
8 in
Step-by-step explanation:
RA = 4 in, RB = 2 in
oil height in A = hA = 2 in
Find oil height in B = hB
volume of oil in A = VA = π*RA² * hA
equal amount means volume of oil in B VB = VA
But VB = π*RB² * hB
so π*RA² * hA = π*RB² * hB
then
hB = hA *(RA/RB)² = 2 * (4/2)² = 8 in
0.42z = 2.52
z = 2.52 / 0.42
z = 6
same as
z + 7.45 = 13.45
z = 13.45 - 7.45
z = 6
answer is top right z + 7.45 = 13.45
Answer:
the relation is NOT a function
domain: {
1,-2,1}
range: {
-2, 0, 2, 3}
Step-by-step explanation: