Answer:By definition, perpendicular line are two lines that intersect at right angles. In other words, the angle made by two lines should be 90°. Therefore, the use of distance formula does not help because it only tells you if the sides are equal. It does not tell you about the intercepted angle.
A technique that can help you to know if two straight lines are perpendicular is is you find their slopes. Let's say the slope of line 1 is m1 and the slope of line 2 is m2. If m1*m2 yields a product of -1, then the lines are perpendicular. This is because if m1 is the negative reciprocal of m2, the lines are perpendicular. But if m1=m2, the lines are parallel, meaning they don't intersect at all.
Therefore, the answer is: Find the slopes and show that their product is -1.
hope it help
Answer:
115.48
Step-by-step explanation:
This shape can be split into two distinct shapes
Two halves of a semi circle, and a rectangle in between
Circle:
Putting both halves of the semi circle together will give you a full circle. The diameter of the circle is given (7m).
The area of a circle is A = π 
The radius, r, is half of the diameter, so 7 / 2 = 3.5m
A = π
A = π * 
A = 38.38
Rectangle:
The area of a rectangle is A = h b
The height, h, is known at 7m
The base, b, can be found by removing the length from the dot to the end of the semi circles. This length is the radius of the semi circles, 3.5m
Removing the radius from the total length given
18 - 3.5 - 3.5 = 11m
The base is 11m
A = h b
A = 7 * 11 = 77
Total Area = Circle area + Rectangle area
Total Area = 38.38 + 77 = 115.48
Each ream weighs 5 lb . so, reducing 10 lb means removing 2 reams from the 12. so, how do we arrange the 10 reams so that its easy to carry?
i thinks that 3 stacks will not work as it wont be a symmetric arrangement as 1 will be left out. So, 2 stacks of 5 each would be easy to carry. but the stacks should be placed in such a way that the lengths are parallel to each other and not in-line which would increase the length making it comparatively longer. its easier to hold a (2*8.5,11,2*5=17,11,17)compact box.
