Answer:
(0, 1)
General Formulas and Concepts:
<u>Pre-Algebra</u>
Order of Operations: BPEMDAS
- Brackets
- Parenthesis
- Exponents
- Multiplication
- Division
- Addition
- Subtraction
Equality Properties
<u>Algebra I</u>
- Solving systems of equations using substitution/elimination
Step-by-step explanation:
<u>Step 1: Define Systems</u>
y + 5x = 1
5y - x = 5
<u>Step 2: Rewrite Systems</u>
y + 5x = 1
- Subtract 5x on both sides: y = 1 - 5x
<u>Step 3: Redefine Systems</u>
y = 1 - 5x
5y - x = 5
<u>Step 4: Solve for </u><em><u>x</u></em>
<em>Substitution</em>
- Substitution in <em>y</em>: 5(1 - 5x) - x = 5
- Distribute 5: 5 - 25x - x = 5
- Combine like terms: 5 - 26x = 5
- Isolate <em>x</em> term: -26x = 0
- Isolate <em>x</em>: x = 0
<u>Step 5: Solve for </u><em><u>y</u></em>
- Define equation: 5y - x = 5
- Substitute in <em>x</em>: 5y - 0 = 5
- Subtract: 5y = 5
- Isolate <em>y</em>: y = 1
Answer:
d/c = 8
Step-by-step explanation:
f(x) = 5.4321×2^×
f(4) = 5.4321×2^4 = d
f(1) = 5.4321×2^1 = c
d/c = (5.4321×2^4)/(5.4321×2^1) = 2^3 = 8
Work it exactly like the other one with Wilda and Karla.
Juan takes 15 hours to do a job ... he does 1/15 of it in an hour.
His father can do it in 6 hours ... he does 1/6 of it in an hour.
Juan works alone for 4.5 hours. In that time, he does 4.5/15 = 0.3
of the job. When his father joins him, there's only 0.7 of it to finish.
Working together, they do (1/15 + 1/6) = (2/30 + 5/30) = 7/30 of the job
each hour.
How many times do they have to do 7/30 of the job in order to finish
the 7/10 of it that remains ? That will be the number of hours they need.
(7/10) / (7/30) = 7/10 x 30/7 = <em>3 hours</em>.
Then they can knock off while it's still daylight, and go for a swim.
Answer:
410.625
Step-by-step explanation:
