When glucose is high, cAMP is low; CAP does not bind the lac operator, and RNA polymerase does not bind the lac promoter. CAP is only active when glucose levels are low, which means the cAMP levels are high, and therefore the lac operon can only be transcribed at high rate when glucose is absent. The importance of this is that the bacteria only turns on the lac operon and start using lactose only after they have used up all the preferred energy source which is glucose.
The answer is; producing a unique antibody from all other B cells by genomic rearrangement.
An isolated B cell produces monoclonal antibodies (also called Immunoglobulins). Different B cell types produce different types of antibodies (hence the serum of an animal has polyclonal antibodies). Memory B cells are developed when a particular infection is eradicated by the immune system. These B cells proliferate when the infection returns by producing the same antibodies that were effective against the foreign entity.
Protection of certain species is a very controversial topic. Many species like the mountain lion or jaguar that are near extinction in certain areas, are threats to human life. Another reason is that they could off set the food chain when they come back and be stonger than ever. For example the mountian lion could eat out the thriving white tail deer population which was struggling because of the mountain lion. And many people rely on white tail deer for food.
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Answer:
A) A single base pair change.
Explanation:
Point mutation is a change in a single base pair of a nucleotide. This comes as a results of mistakes made during DNA replication, induced by ultravoilet radiations, extreme heat and X-rays. There are three types of point or substitution mutations; change, deletion and insertion. The nucleotide bases are either mistakenly inserted, changed or deleted, thus changing the resulting protein or amino acid being coded for.
