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3 years ago

!!CHECK MY ANSWERS!!

Mathematics

1 answer:

AlekseyPX3 years ago

4 0

I think you're right. I'm in pre-algebra, and sucks at it. Yet, I keep a A.

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What is the answer to these three questions

USPshnik [31]

Answer:

Step-by-step explanation:

x + 3 = 2(x - 6)

x + 3 = 2x - 12

-1x = -15

$\frac{-15}{-1}$ =15

6 0

3 years ago

My homework asked my this ''i am a 3-digit number.If you add 220 to my number,it is 847 what is my number .But im having trouble

Ostrovityanka [42]

Answer: Your answer is 627

Step-by-step explanation: If you add 220 to 627, it becomes 847. You can find out by taking away 220 from 847 because the answer would be the same anyways.

3 0

3 years ago

Read 2 more answers

What is the midpoint of the segment shown below?

aleksandr82 [10.1K]

Answer:

$Mid\ points = (\frac{5}{2} , \frac{7}{2})$ .

Step-by-step explanation:

Given : End points of line are (3, 5) and ( 2 , 2) .

To find : What is the midpoint of the line .

Solution : We have given

End points(3, 5) and ( 2 , 2) .

$Mid\ points = (\frac{x_{1}+x_{2}}{2} , \frac{y_{1}+y_{2}}{2})$ .

Here ,

$x_{1} = 3.\\x_{2} = 2.\\y_{1} = 5.\\y_{2} = 2$ .

The plug the values in given formula.

$Mid\ points = (\frac{3+ 2}{2} , \frac{ 5+2}{2})$

$Mid\ points = (\frac{5}{2} , \frac{7}{2})$ .

Therefore, D). $Mid\ points = (\frac{5}{2} , \frac{7}{2})$ .

4 0

4 years ago

Determine whether each pair of ratios are equivalent ratios. Write yes or no.

Setler79 [48]

Answer:

MEOW.....................

Step-by-step explanation:

7 0

3 years ago

Futhe Mathematics <img src="https://tex.z-dn.net/?f=%28Cos%20%7B%7D%5E%7B4%7Dt%20-Sin%20%7B%7D%5E%7B4%7Dt%20%29%20%20%5Cdiv%2

Nastasia [14]

Answer:

cos2t/cos²t

Step-by-step explanation:

Here the given trigonometric expression to us is ,

$\longrightarrow \dfrac{cos^4t - sin^4t }{cos^2t }$

We can write the numerator as ,

$\longrightarrow \dfrac{ (cos^2t)^2-(sin^2t)^2}{cos^2t }$

Recall the identity ,

$\longrightarrow (a-b)(a+b)=a^2-b^2$

Using this we have ,

$\longrightarrow \dfrac{(cos^2t + sin^2t)(cos^2t-sin^2t)}{cos^2t}$

Again , as we know that ,

$\longrightarrow sin^2\phi + cos^2\phi = 1$

Therefore we can rewrite it as ,

$\longrightarrow \dfrac{1(cos^2t - sin^2t)}{cos^2t}$

Again using the first identity mentioned above ,

$\longrightarrow \underline{\underline{\dfrac{(cost + sint )(cost - sint)}{cos^2t}}}$

Or else we can also write it using ,

$\longrightarrow cos2\phi = cos^2\phi - sin^2\phi$

Therefore ,

$\longrightarrow \underline{\underline{\dfrac{cos2t}{cos^2t}}}$

And we are done !

$\rule{200}{4}$

Additional info :-

Derivation of cos²x - sin²x = cos2x :-

We can rewrite cos 2x as ,

$\longrightarrow cos(x + x )$

As we know that ,

$\longrightarrow cos(y + z )= cosy.cosz - siny.sinz$

So that ,

$\longrightarrow cos(x+x) = cos(x).cos(x) - sin(x)sin(x)$

On simplifying,

$\longrightarrow cos(x+x) = cos^2x - sin^2x$

Hence,

$\longrightarrow\underline{\underline{cos (2x) = cos^2x - sin^2x }}$

$\rule{200}{4}$

7 0

3 years ago