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WINSTONCH [101]
1 year ago
15

Please give the answer

Mathematics
1 answer:
Alex1 year ago
7 0

Step-by-step explanation:

<u><em>f(a):</em></u>

   So for this you simply plug in "a" as x, and this doesn't really do anything beside replace all values with x, so you just have the equation:

  f(a) = 5a+4

<u><em>2 f(a):</em></u>

   So for this one, you want to represent f(a) using the equation it's equal to (5a + 4), and substitute it in for f(a). In doing so, you get the expression:

   2*f(a) -> 2(5a + 4) -> 10a + 8

<u><em>f(2a):</em></u>

   So this is very similar to the first question, although you will have to do some multiplication. So just plug in 2a as "x" to get the equation:

   f(2a) = 5(2a) + 4 = 10a+4

<u><em>f(a+2):</em></u>

   Basically the same process, you plug in (a+2) as "x" and simplify:

   f(a+2) = 5(a+2) + 4\\f(a+2) = 10a+10+4\\f(a+2) = 10a+14

<u><em>f(a) + f(2)</em></u>:

  This is similar to the second question, and you simply want to replace the f(a) with the equation that represents it (5a + 4) and same thing for f(2) = 5(2) + 4

   f(a) + f(2) = (5a+4)+(5(2)+4) \\f(a) + f(2) = (5a+4)+(10+4)\\f(a)+f(2) = (5a+4) + (14)\\f(a) + f(2) = 5a+18

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X÷x+4=3÷x-1<br><img src="https://tex.z-dn.net/?f=%20%5Cfrac%7Bx%7D%7Bx%20%2B%204%7D%20%20%3D%20%20%5Cfrac%7B3%7D%7Bx%20-%201%7D%
butalik [34]

\frac{x}{x + 4}=\frac{3}{x - 1} \\3(x+4) = x(x-1)\\3x+12 =x^2-x\\0=x^2-4x-12\\0=(x-6)(x+2)\\X= 6, -2


Steps:

First we cross multiply

Then Distribute,

Then move all terms to one side

Factor

Set each factor equal to zero

6 0
2 years ago
Check
Westkost [7]

Answer:

I think it's the 3rd one

Step-by-step explanation:

because it makes sense

3 0
3 years ago
Find the interval(s) where the function is increasing and the interval(s) where it is decreasing. (Enter your answers using inte
Mashcka [7]

Answer:

f'(x) > 0 on (-\infty ,\frac{1}{e}) and f'(x)<0 on(\frac{1}{e},\infty)

Step-by-step explanation:

1) To find and interval where any given function is increasing, the first derivative of its function must be greater than zero:

f'(x)>0

To find its decreasing interval :

f'(x)

2) Then let's find the critical point of this function:

f'(x)=\frac{\mathrm{d} }{\mathrm{d} x}[6-2^{2x}]=\frac{\mathrm{d} }{\mathrm{d}x}[6]-\frac{\mathrm{d}}{\mathrm{d}x}[2^{2x}]=0-[ln(2)*2^{2x}*\frac{\mathrm{d}}{\mathrm{d}x}[2x]=-ln(2)*2^{2x}*2=-ln2*2^{2x+1\Rightarrow }f'(x)=-ln(2)*2^{2x}*2\\-ln(2)*2^{2x+1}=-2x^{2x}(ln(x)+1)=0

2.2 Solving for x this equation, this will lead us to one critical point since x'  is not defined for Real set, and x''=\frac{1}{e}≈0.37 for e≈2.72

x^{2x}=0 \ni \mathbb{R}\\(ln(x)+1)=0\Rightarrow ln(x)=-1\Rightarrow x=e^{-1}\Rightarrow x\approx 2.72^{-1}x\approx 0.37

3) Finally, check it out the critical point, i.e. f'(x) >0 and below f'(x)<0.

8 0
3 years ago
Hey yall! i dont need the math just the answers!
Inessa05 [86]

Answer:

13A. 14, 48, 50

13B. both mulitpled by 2?

13C. 56, 125

14. Yes

Step-by-step explanation:

3 0
2 years ago
Read 2 more answers
John wants to buy a new laptop computer the computer store sells laptops for $480 or 9 credit payments of $58 how much interest
Neko [114]
First you would need to find out how many 9 payments of 58$ would be and that is 522. Then you would need to subtract the 522 and the 480 and your answer would be 42$ so the interest would be 42$
5 0
3 years ago
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