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3 years ago

9

Find the area in this picture

1 answer:

nikklg [1K]3 years ago

5 0

The area is 80 just time 10 and 2 and 4

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How many solutions does y=−2x−4<br> y=3x+3 have<br><br>

Wewaii [24]

Answer:

There is one solution

8 0

2 years ago

Read 2 more answers

Help! NO LINKS!!!<br> I need an answer so if anyone can help,please do!

Ierofanga [76]

It’s A !! I’m 100% sure

6 0

2 years ago

ving as a relation, state the domain and range, then determine if it is a6.2X-2 0.-2Relation:DomainRangeFunction3 i

Travka [436]

The relation is the set of ordered pairs of point drawn in the graph

The points are:

(-2, 3), (0, 1), (2, -1), (3, -2)

So the relation is:

R = {(-2, 3), (0, 1), (2, -1), (3, -2)}

The domain is the values of x in the ordered pairs

x = -2, 0, 2, 3

The domain = {-2, 0, 2, 3}

The range is the values of y in the ordered pairs

y = 3, 1, -1, -2

Arrange them in the set

The range = {-2, -1, 1, 3}

7 0

1 year ago

If 8x = 48, then x = ___. (Only input whole number) Numerical Answers Expected! Answer for Blank 1:

Leno4ka [110]

Answer:

x = 6

Step-by-step explanation:

8x = 48,

Divide each side by 8 to isolate x

8x/8 = 48/8

x = 6

5 0

3 years ago

Find the value of the variable.

Nikolay [14]

we are given that

both sides are equal

so, their length must be equal

$HK=\sqrt{(p-1)^2+(5-2)^2}$

$HK=\sqrt{(p-1)^2+9}$

now, we can find other side

$JK=\sqrt{(p-7)^2+(5-2)^2}$

$JK=\sqrt{(p-7)^2+9}$

now, we can set them equal

$HK=JK$

$\sqrt{(p-1)^2+9}=\sqrt{(p-7)^2+9}$

now, we can take square both sides

$(p-1)^2+9=(p-7)^2+9$

now, we can solve for p

$(p-1)^2=(p-7)^2$

$p^2-2p+1=p^2-14p+49$

$-2p+1=-14p+49$

$12p=48$

$p=4$ ..............Answer

4 0

2 years ago