Find the area in this picture

Mathematics

1 answer:

nikklg [1K]3 years ago

5 0

The area is 80 just time 10 and 2 and 4

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Can someone help me with this please ?

vaieri [72.5K]

Answer:

3.36 cm

Step-by-step explanation:

from the passage before ; the figure of question is similar to the first figure in passage because those triangles have an each equal angle.

Therefore the ratio of side is equal ; 1/0.84=4/x

Solve equation will be x(1)=4(0.84) ; x=3.36 cm

5 0

3 years ago

Objects A and B are in harmonic motion modeled by

Zepler [3.9K]

Answer:

The phase difference between yA and yB is $\frac{-\pi }{12}$

Step-by-step explanation:

Given harmonic modeled as :

yA = 8 sin(2t - $\frac{\pi }{3}$ ) And

yB = 8 sin(2t - $\frac{\pi }{4}$ )

The function as written as :

y = a sin(ωt - Ф) where Ф is phase difference

So , phase difference between yA and yB = ( Ф_1 - Ф_2 )

Or phase difference between yA and yB = ( - $\frac{\pi }{3}$ + $\frac{\pi }{4}$ )

Or, phase difference between yA and yB = $(\frac{-4\pi +3\pi }{12})$

I.e phase difference between yA and yB = $\frac{-\pi }{12}$

Hence The phase difference between yA and yB is $\frac{-\pi }{12}$ Answer

4 0

4 years ago

Read 2 more answers

What is the derivative of the function below?

11111nata11111 [884]

$g(x)=4x-\dfrac{1}{4x}=4x-(4x)^{-1}\\\\\\\\g'(x)=\left[4x-(4x)^{-1}\right]'=(4x)'-\left[(4x)^{-1}\right]'=4-[-1(4x)^{-2}]\cdot4\\\\=4+\dfrac{1}{(4x)^2}\cdot4=4+\dfrac{4}{4^2x^2}=\boxed{4+\dfrac{1}{4x^2}}\\\\Used:\\\\(f(x)-g(x))'=f'(x)-g'(x)\\\\.[f(g(x))]'=f'(g(x))\cdot g'(x)\\\\(x^n)'=nx^{n-1}$