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Tems11 [23]
3 years ago
9

Objects A and B are in harmonic motion modeled by

Mathematics
2 answers:
Zepler [3.9K]3 years ago
4 0

Answer:

The phase difference between yA and yB is  \frac{-\pi }{12}

Step-by-step explanation:

Given harmonic modeled as :

yA = 8 sin(2t  - \frac{\pi }{3})         And

yB = 8 sin(2t  - \frac{\pi }{4})

The function as written as :

y = a sin(ωt  - Ф)  where  Ф is phase difference

So , phase difference between yA   and  yB = ( Ф_1 - Ф_2 )

Or phase difference between yA   and  yB = ( -  \frac{\pi }{3} + \frac{\pi }{4} )

Or, phase difference between yA   and  yB = (\frac{-4\pi +3\pi }{12})

I.e phase difference between yA   and  yB =\frac{-\pi }{12}

Hence The phase difference between yA and yB is \frac{-\pi }{12}   Answer

galina1969 [7]3 years ago
4 0

Answer:

  -π/12

Step-by-step explanation:

yA has a phase shift of -π/3; yB has a phase shift of -π/4. The difference between their phases is ...

  -π/3 -(-π/4) = (-4/12 +3/12)π = -π/12

yA lags yB by π/12 radians.

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