Question

Objects A and B are in harmonic motion modeled by

Answer 1

Answer:

The phase difference between yA and yB is  $\frac{-\pi }{12}$

Step-by-step explanation:

Given harmonic modeled as :

yA = 8 sin(2t  - $\frac{\pi }{3}$)         And

yB = 8 sin(2t  - $\frac{\pi }{4}$)

The function as written as :

y = a sin(ωt  - Ф)  where  Ф is phase difference

So , phase difference between yA   and  yB = ( Ф_1 - Ф_2 )

Or phase difference between yA   and  yB = ( -  $\frac{\pi }{3}$ + $\frac{\pi }{4}$ )

Or, phase difference between yA   and  yB = $(\frac{-4\pi +3\pi }{12})$

I.e phase difference between yA   and  yB =$\frac{-\pi }{12}$

Hence The phase difference between yA and yB is $\frac{-\pi }{12}$   Answer

Answer 2

Answer:

  -π/12

Step-by-step explanation:

yA has a phase shift of -π/3; yB has a phase shift of -π/4. The difference between their phases is ...

  -π/3 -(-π/4) = (-4/12 +3/12)π = -π/12

yA lags yB by π/12 radians.