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3 years ago

Find the LCM of the numbers 12, 17 using the prime factorization

Mathematics

1 answer:

Makovka662 [10]3 years ago

3 0

LCM of 12 and 17 = 204

Hope this helps!

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I don’t quite understand this problem could someone help me please

ale4655 [162]

Answer:

$\frac{7\sqrt{65}}{65}$

Step-by-step explanation:

Cosine is the ratio of the side adjacent to the angle and the right triangle hypotenuse.

$cos$ B = $\frac{7}{\sqrt{65}}$ = $\frac{7\sqrt{65}}{65}$

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2 years ago

0.7070707070 is an irrational number

zaharov [31]

False irrationals number have no end with no patterns (example would be pi)

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3 years ago

What is the least common multiple of 4 and 12? O 4 O 12 O 24 o ) 48

densk [106]

Answer:

Step-by-step explanation:

Least common multiple means what is the smallest number that both numbers go into

List the prime factors

4= 2*2

12 = 2*2*3

The factors that are in needed to make both are 2 and 3

We need 2 of the 2's and 1 3

2*2*3 = 12

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2 years ago

Objective 1.1 6. The graph below represents the equation y=1/2x+1. Which graph best represents the equation created when the slo

Genrish500 [490]

Answer:

The correct answer is B

Step-by-step explanation:

When y=x+1is changed to 4 the slop changes too

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2 years ago

Which equation does this image represent?

nirvana33 [79]

Given:

Image of the ellipse

To find:

The equation of the image

Solution:

The given image is a ellipse.

Center of the ellipse = (0, 0)

x-axis points are (-3, 0) and (3, 0).

y-axis points are (2, 0) and (-2, 0).

Standard form of equation of ellipse:

$$\frac{(x-h)^{2}}{a^{2}}+\frac{(y-k)^{2}}{b^{2}}=1$

where (h, k) is the center = (0,0)

a is the point on x-axis where y = 0. Hence a = 3.

b is the point on y-axis where x = 0. Hence b = 2.

Substitute this in the standard form of ellipse.

$$\frac{(x-0)^{2}}{3^{2}}+\frac{(y-0)^{2}}{2^{2}}=1$

$$\frac{x^{2}}{9}+\frac{y^{2}}{4}=1$

To make the denominator same multiply 1st term by $\frac{4}{4}$ and 2nd term by $\frac{9}{9}$ .

$$\frac{4x^{2}}{4\times9}+\frac{9y^{2}}{9\times4}=1$

$$\frac{4x^{2}}{36}+\frac{9y^{2}}{36}=1$

$$\frac{4x^{2}+9y^{2}}{36}=1$

Multiply by 36 on both sides

$$\frac{4x^{2}+9y^{2}}{36}\times 36=1\times 36$

$${4x^{2}+9y^{2}}={36}$

The equation of the image is $${4x^{2}+9y^{2}}={36}$ .

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3 years ago