Subtract three from either side. That will give you 4r=-21. Divide -21 by 4 and r will equal -5.25.
Assuming no cubes are hidden from view, the base view (as if you're looking from underneath the figure) would have a 2 x 2 square of cubes, plus one at the top. This means that your correct choice would be the one I've attached.
Answer:
n > 96
Therefore, the number of samples should be more than 96 for the width of their confidence interval to be no more than 10mg
Step-by-step explanation:
Given;
Standard deviation r= 25mg
Width of confidence interval w= 10mg
Confidence interval of 95%
Margin of error E = w/2 = 10mg/2 = 5mg
Z at 95% = 1.96
Margin of error E = Z(r/√n)
n = (Z×r/E)^2
n = (1.96 × 25/5)^2
n = (9.8)^2
n = 96.04
n > 96
Therefore, the number of samples should be more than 96 for the width of their confidence interval to be no more than 10mg
The answer is 33
3(-2)^2+4(-2)+5
-6^2+ (-8) + 5
36 + (-8) + 5
28+5
33
A=adult tickets
c=chlderenticekts
s=sinior tickets
a=c
a+c+s=120
2a+s=120
total made is 1100
12a+6c+10s=1100
sub
a=c
12a+6a+10s=1100
add
18a+10s=1100
multiply first equation by -9 and add to other equation
-18a-9s=-1080
18a+10s=1100 +
0a+s=20
s=20
20 senior tickets were sold
answer is B
