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Stolb23 [73]
3 years ago
6

What is the equation of the line that passes through the point (-2,-2) and has a slope of 4?

Mathematics
1 answer:
sveta [45]3 years ago
5 0
Y = 4x + b
Plug in point
-2 = 4(-2) + b, b = 6
Solution: y = 4x + 6
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the zeros of a parabola are -4 and 2, and (6, 10) is a point on the graph. which equation can be solved to determine the value o
natka813 [3]
Sure this question comes with a set of answer choices.

Anyhow, I can help you by determining one equation that can be solved to determine the value of a in the equation.

Since, the two zeros are - 4 and 2, you know that the equation can be factored as the product of (x + 4) and ( x - 2) times a constant.  This is, the equation has the form:

y = a(x + 4)(x - 2)

Now, since the point (6,10) belongs to the parabola, you can replace those coordintates to get:

10 = a (6 + 4) (6 - 2)

Therefore, any of these equivalent equations can be solved to determine the value of a:

10 = a 6 + 40) (6 -2)

10 = a (10)(4)

10 = 40a
7 0
3 years ago
Read 2 more answers
How heavy is 24 carat gold?
fomenos
<span>24k gold is also called pure gold or 100 per cent gold. This means that all 24 parts in the gold are all pure gold without traces of any other metals. It is known to be 99.9 per cent pure and takes on a distinct bright yellow color. There is no higher form of gold than 24K and you must be aware of this before you go to a dealer who might tell you that they’re selling you 25K or 26K gold. Since this is the purest form of gold, it is naturally more expensive than 22K or 18K gold. However, this type of gold is lesser in density as compared to gold of a lower karatage which makes it soft and pliable. Hence, it is not suited for regular forms of jewellery. Coins and bars are mostly bought of 24K gold purity. 24K gold is also used in electronics and medical devices such as those used for children suffering from ear infections who are fitted with gold tympanostomy tubes that are known to improve aeration of the middle ear.</span>
5 0
3 years ago
PLZ HELP !! Which of the points (s, t) is not one of the vertices of the shaded region of the
stira [4]

Answer:

A(0,10)

Step-by-step explanation:

Given the 4 inequalities:

s ≥ 12 - 0.5t (1)

s ≥ 10 -t (2)

s ≤ 20-t (3)

s ≥ 0

t ≥ 0

Let analyse all 4 possible answer:

  • A(0, 10)

Let substitute this point into (1) we have: 10 ≥ 12 -0.5*0 Wrong

We do not choose A

  • B (0, 20)

Let substitute this point into (1) we have: 20 ≥ 12 -0.5*0  True

Let substitute this point into (2) we have: 20 ≥ 10 - 0 True

Let substitute this point into (3) we have: 20 ≤ 20 - 0 True

We choose B as the vertex

  • C. (4, 16)

Let substitute this point into (1) we have: 16 ≥ 12 -0.5*4  True

Let substitute this point into (2) we have: 16 ≥ 10 - 4 True

Let substitute this point into (3) we have: 16 ≤ 20 - 4 True

We choose C as the vertex

  • D. (16,4)

Let substitute this point into (1) we have: 4 ≥ 12 -0.5*16 True

Let substitute this point into (2) we have: 4 ≥ 10 - 16 True

Let substitute this point into (3) we have: 4 ≤ 20 - 16 True

We choose B as the vertex

Hence, the point A(0,10)  is not one of the vertices of the shaded region of the  set of inequalities.

3 0
3 years ago
PLEASE HELP 75 POINTS: What is the length of time a loan will last if it has a rate of 0.02, a principal of $500, and it accrued
AlladinOne [14]
To reduce the time, the rate should be increased or the interest should be decreased

4 0
3 years ago
PLEASE HELP ME I ASAP<br><br>I WILL MARK YOU BRAINLIEST
kramer
<h3>Function 1 : </h3>

Observe the abscicca and ordinates

<u>*</u><u>Note</u><u> </u><u>that</u><u>:</u><u>-</u><u> </u><em>y-coordinate</em><em> </em><em>is</em><em> </em><em>ordinate</em><em> </em><em>and</em><em> </em><em>x-coordinate</em><em> </em><em>is</em><em> </em><em>abscicca</em><em>.</em>

  • The ordinate having 0 as abscicca in function 1 is (0,1), Thus.. The y-intercept is 1

<h3>Function 2 : </h3>

Observe the graph and mark the point where function meets y-axis

<u>*</u><u>Note</u><u> </u><u>that</u><u>:</u><u>-</u><u> </u><em>The</em><em> </em><em>point</em><em> </em><em>of</em><em> </em><em>the</em><em> </em><em>graph</em><em> </em><em>where</em><em> </em><em>the</em><em> </em><em>function</em><em> </em><em>meets</em><em> </em><em>y-axis</em><em> </em><em>is</em><em> </em><em>called</em><em> </em><em>y-intercept</em><em>.</em>

  • The point where the function meets is (0,1). Therefore, The y-intercept of function 2 is also 1

\red{ \rule{35pt}{2pt}} \orange{ \rule{35pt}{2pt}} \color{yellow}{ \rule{35pt} {2pt}} \green{ \rule{35pt} {2pt}} \blue{ \rule{35pt} {2pt}} \purple{ \rule{35pt} {2pt}}

<em><u>Thus, Option C is the correct choice!!~</u></em>

7 0
3 years ago
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