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wlad13 [49]
4 years ago
6

Find the distance between the points (0,10) and (-9,1)

Mathematics
1 answer:
likoan [24]4 years ago
7 0

\bf ~~~~~~~~~~~~\textit{distance between 2 points} \\\\ (\stackrel{x_1}{0}~,~\stackrel{y_1}{10})\qquad (\stackrel{x_2}{-9}~,~\stackrel{y_2}{1})\qquad \qquad d = \sqrt{( x_2- x_1)^2 + ( y_2- y_1)^2} \\\\\\ d=\sqrt{(-9-0)^2+(1-10)^2}\implies d=\sqrt{(-9)^2+(-9)^2} \\\\\\ d=\sqrt{81+81}\implies d=\sqrt{162}\implies d\approx 12.73

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Answer:

153 cups of butter

Step-by-step explanation:

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5 0
3 years ago
Problem PageQuestion Calcium levels in people are normally distributed with a mean of mg/dL and a standard deviation of mg/dL. I
SIZIF [17.4K]

Complete Question

The complete question is shown on the first uploaded image

Answer:

The  calcium level that is the borderline between low calcium levels and those not considered low is  c = 8.68

Step-by-step explanation:

From the question we are told that

    The mean is  \mu =  9.5\  mg/dL

     The standard deviation \sigma =  0.5 \ mg/dL

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Let X be a X random calcium level

  Now the  P(X < c) = 0.05

Here P denotes probability

        c is population with calcium level at the borderline

  Since the calcium level is normally distributed the z-value is  evaluated as

    P(Z < \frac{c - \mu}{\sigma } ) = 0.05

The critical value for 0.05 from the standard normal distribution table is

       t_{0.05} = -1.645

=>    \frac{c - \mu}{\sigma }  =  -1.645

substituting values

       \frac{c - 9.5}{0.5 }  =  -1.645

=>    c - 9.5 =  -0.8225

=>     c = 8.68

 

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Step-by-step explanation:

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Step-by-step explanation:

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