Since theirs no question...
The formula for PT:
a^+b^=c^
Two thirds.
1/3 +1/3 = 2/3.
You don’t add the denominator (bottom terms), you only add the numerators (the top terms)
Answer:
s = 21.16
Step-by-step explanation:
0.5s +1= 7+ 4.58
Combine like terms
0.5s +1=11.58
Subtract 1 from each side
0.5s +1-1= 11.58-1
.5s = 10.58
Multiply by 2
.5s *2 = 10.58*2
s = 21.16
Answer:
Step-by-step explanation:

Hence proved!
Answer:
14.42inches
Step-by-step explanation:
Given the following
b = 5 in
c = 8in
we are to find the measure of the space diagonal line
Using the pythagoras theoreml
l^2 = b^2 + c^2
l^2 = 13^2 - 5^2
l^2 = 169 -25
l^2 = 144
l = 12in
To get the measure of the space diagonal line in the box, we will use the pythagoras theorem;
s^2 = l^2 + c^2
s^2 = 144 + 8^2
s^2 = 144 + 64
s^2 = 208
s= 14.42inches
Hence the required length ix 14.42inches