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Nikitich [7]
3 years ago
13

What is the answer for number 11

Mathematics
1 answer:
IRINA_888 [86]3 years ago
6 0
No, because you have two y-points that are the same.
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How many password are possible if you want to use 5 letters and they cannot be repeated.
hram777 [196]

Answer:

100,000 possible passwords

Step-by-step explanation:

5 vowels, each of the letters in the password can be chosen: 5^5=3125.

If it's case sensitive, then there's 10 choices for each character: 5^10= 100,000

3 0
3 years ago
Kind of easy giving alot points to anyone who knows​
kotykmax [81]

Answer:

5 hours

Step-by-step explanation:

6 0
3 years ago
24)<br> 12<br> 21<br> X<br> 84<br> 91<br> 28
padilas [110]

Answer:

13

Step-by-step explanation:

12×7 = 84,

so the scale ratio is 1/7

now 91×1/7

= 91/7

= 13

5 0
3 years ago
How many weeks of data must be randomly sampled to estimate the mean weekly sales of a new line of athletic footwear? We want 98
Irina18 [472]

Answer:

n=(\frac{2.33(1400)}{400})^2 =66.50 \approx 67

So the answer for this case would be n=67 rounded up

Step-by-step explanation:

Information given

\bar X represent the sample mean for the sample  

\mu population mean

\sigma=1400 represent the sample standard deviation

n represent the sample size  

Solution to the problem

The margin of error is given by this formula:

ME=z_{\alpha/2}\frac{\sigma}{\sqrt{n}}    (a)

And on this case we have that ME =400 and we are interested in order to find the value of n, if we solve n from equation (a) we got:

n=(\frac{z_{\alpha/2} \sigma}{ME})^2   (b)

The critical value for 98% of confidence interval now can be founded using the normal distribution. And the critical value would be z_{\alpha/2}=2.33, replacing into formula (b) we got:

n=(\frac{2.33(1400)}{400})^2 =66.50 \approx 67

So the answer for this case would be n=67 rounded up

8 0
3 years ago
Land's Bend sells a wide variety of outdoor equipment and clothing. The company sells both through mail order and via the intern
nata0808 [166]

Answer:

−35.713332 ; 0.313332

Step-by-step explanation:

Given that:

Sample size, n1 = 11

Sample mean, x1 = 79

Standard deviation, s1 = 18.25

Sample size, n2 = 18

Sample mean, x2 = 96.70

Standard deviation, s2 = 20.25

df = n1 + n2 - 2 ; 11 + 18 - 2 = 27

Tcritical = T0.01, 27 = 2.473

S = sqrt[(s1²/n1) + (s2²/n2)]

S = sqrt[(18.25^2 / 11) + (20.25^2 / 18)]

S = 7.284

(μ1 - μ2) = (x1 - x2) ± Tcritical * S

(μ1 - μ2) = (79 - 96.70) ± 2.473*7.284

(μ1 - μ2) = - 17.7 ± 18.013332

-17.7 - 18.013332 ; - 17.7 + 18.013332

−35.713332 ; 0.313332

3 0
2 years ago
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