Which of the following equations was used to graph the line shown?

Mathematics

1 answer:

kirza4 [7]4 years ago

5 0

The answer is d because y intercept is -3

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If one factor of 6.x2 + 5x – 6 is

sattari [20]

C. 2x + 3

You have many ways to solve this!
You could...

A) multiply all the answer choices by 3x-2 and see what matches

B) Factor the trinomial

C) Divide the trinomial by the binomial using long division

7 0

3 years ago

Read 2 more answers

Use the decimals 2.47, 9.57, and 7.1 to write two different addition facts and two different subtraction facts

kaheart [24]

2.47+7.1=9.57
7.1+2.47=9.57
9.57-2.47=7.1
9.57-7.1=2.47

3 0

3 years ago

Round to the nearest thousands 3475.6993

Andreyy89

3475.699

°°°°°°°°°°°°°°°

Am I correct?

4 0

3 years ago

I need help w/ this!! thank you

Fittoniya [83]

<h3>Answer:</h3>

$\boxed{\pink{\sf \leadsto Yes \ there \ is \ a \ solution \ of \ the \ given \ inequality .}}$

<h3>Step-by-step explanation:</h3>

A inequality is given to us and we need to convert it into standard form and see whether if it has a solution . So let's solve the inequality.

The inequality given to us is :-

$\bf\implies |2y + 3 | - 1 \leq 0 \\\\\bf\implies |2y+3|\leq 1 \\\\\bf\implies (|2y+3|)^2 \leq 1^2 \\\\\bf\implies (2y+3)^2 \leq 1 \\\\\bf\implies (2y)^2+3^2+2(2y)(3) \leq 1 \\\\\bf\implies 4y^2+9+12y - 1 \leq 0 \\\\\bf\implies 4y^2+12y+8 \leq 0 \\\\\bf\implies 4( y^2 + 3y + 2 ) \leq 0 \\\\\bf\implies y^2+3y +2 \leq 0 \:\:\bigg\lgroup \purple{\bf Standard \ form \ of \ inequality }\bigg\rgroup \\\\\bf\implies y^2y+2y+y+2 \leq 0 \\\\\bf\implies y(y+2)+1(y+2)\leq 0 \\\\\bf\implies ( y+2)(y+1)\leq 0 \\\\\bf\implies \boxed{\red{\bf y \leq (-2) , (-1) }}$