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Novay_Z [31]
3 years ago
9

I'll give brainliest answer

Mathematics
1 answer:
Serhud [2]3 years ago
4 0

Answer:

Part 1) m\angle x=105^o

Part 2) m\angle y=75^o

Part 3) m\angle z=86^o

part 4) m\angle w=94^o

Step-by-step explanation:

step 1

Find the value of x

we know that

m\angle x+75^o=180^o ----> by supplementary angles (form a linear pair)

m\angle x=180^o-75^o

m\angle x=105^o

step 2

Find the value of y

we know that

m\angle y=75^o ----> by alternate  interior angles

step 3

Find the value of z

we know that

m\angle z=86^o ----> by vertical angles

step 4

Find the value of w

we know that

m\angle w+m\angle z=180^o ----> by consecutive interior angles

we have

m\angle z=86^o

m\angle w+86^o=180^o

m\angle w=180^o-86^o

m\angle w=94^o

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Liula [17]

Answer:

1) x= 3/2=  1 1/2

2) x=  2/3

Step-by-step explanation:

1)How many times as heavy as  Whiskers is  Piglio?

a) Write a multiplication equation for the question.

2 2/3 kg  * [x]= 4kg

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b) Write a division equation for the question.

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c) Is the answer greater than 1 or less than 1?

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Whiskers is 2/3 times as heavy as Pigilo.

5 0
2 years ago
Need help w this! will give brainliest and thanks to best answer :o) tysm<3
Montano1993 [528]

Answer:

A. They will pay more with the new price plan.

B. The new price plan would be cheaper.

Step-by-step explanation:

A. They will pay more with the new price plan.

For the current price plan, you would add the $3 rent to the two games (which are $4 each). This basically means:

$3 + $4 + $4 = $11

For the new price plan, you would add the $11 rent to the two games (which are $2 each). This basically means:

$11 + $2 + $2 = $15

Therefore, you pay more for the new price plan.

B. Using similar logic as part A, the current price plan 7 games would cost:

$3 + [7 x ($4)] = $31    (multiply by 7 since they play 7 games)

For the newprice plan, 7 games would cost:

$11 +  [7 x ($2)] = $25    (multiply by 7 since they play 7 games)

Therefore, the new price plan would be cheaper.

Hope this helps :)

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2 years ago
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