Answer:

Step-by-step explanation:
To find a line that is perpendicular to 8x + 3y = -6 and goes through (-24, 2), lets first find what the line's slope would be.
We can find this by finding the slope of 8x + 3y = -6 and taking the negative reciprocal of it.
We can find the slope of that line by putting it in slope-intercept form:
8x + 3y = -6
Subtract 8x from both sides.
3y = -6 - 8x
Divide both sides by 3.


So the slope of that line would be -8/3.
The negative reciprocal of -8/3 would be 3/8.
Now we know that the new line would have to pass through the point (-24, 2). We can use this point and write the equation in point-slope form:

Now lets change this into slope-intercept form. Add 2 to both sides.

Distribute the 3/8.

Simplify.

And now we have our equation in slope-intercept form.
I hope you find this helpful.
Answer:
b) 36
Step-by-step explanation:
area= ((sum of parallel lines) / 2) * hight
X = ((8 + (8+4+4))/2) *3
X= ((8+ (16) /2) *3
X= ((24)/2)*3
X= 12*3
x=36
Horizontal shift to the left by 6 points
Answer:
9.56
Step-by-step explanation:
4.78x2 so then your answer would be 9.56
Question a:
f(6) = (6)² + 2(6) + 8
f(6) = 36 + 12 + 8
f(6) = 56
Question b:
f(x+4) = (x+4)² + 2(x+4) + 8
f(x+4) = x² + 8x + 16 + 2x + 8 + 8
f(x+4) = x² + 10x + 32
Question c:
f(-x) = (-x)² + 2(-x) + 8
f(-x) = x - 2x + 8