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Vaselesa [24]
3 years ago
7

Figure ABCD is reflected across the x-axis. What are the coordinates of A' , B' , C' , and D' ? Enter your answer by filling in

the boxes. A' (​ ​, ​ ​) B' (​ ​, ​ ​) C' (​ ​, ​ ​) D' (​ ​, ​ ​) A graph with a quadrilateral on it formed between points A begin ordered pair 2, 3 end ordered pair, B begin ordered pair 5, 5 end ordered pair, C begin ordered pair 7, 3 end ordered pair, and D begin ordered pair 5, 2 end ordered pair
Mathematics
2 answers:
sp2606 [1]3 years ago
5 0

Answer:

Step-by-step explanation:

A' (2,-3)

B' (5,-5)

C' (7,-3)

D' (5,-2)

marin [14]3 years ago
3 0

Answer:

A' (2,-3)

B' (5,-5)

C' (7,-3)

D' (5,-2)

Step-by-step explanation:

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One half the sum of a number z and 3 1/2 is 4 1/2
solong [7]
4 1/2(2)=9. Multiply by 2 to get total
9- 3 1/2=z. Subtract 3 1/2 from total to get Z
5 1/2= Z
3 0
3 years ago
Find the value of the variables in each figure. explain your reasoning
V125BC [204]

Answer:

x=24

y=144

Step-by-step explanation:

y= 144(corresponding angle)

y =(x+12) ( straight angle)

7 0
3 years ago
Create a scenario that leads to an inequality of the form ax + b > c. You can use any of the inequality symbols (>, ≥, &lt
Ann [662]

Answer:

5x +3y>-15

5(0)+3(0)

0+0=   0 > -15

Step by step explanation

We have to create a scenario that leads to an inequality of the form ax + b > c.

Word problem: A family went to an park. Entry fee of the park for a family is $20 and the cost of a ride is $10 per person. The family spent more than $100 on that ride.

The required inequality is

Subtract 20 from both sides.

Divide both sides by 10.

It means the number of rides must be greater than 8.

6 0
3 years ago
Read 2 more answers
Simplify the expression below using the distributive property
Rus_ich [418]

Answer:

-84-12i

Step-by-step explanation:

The one you have is the answer :)

3 0
2 years ago
For fun question
ZanzabumX [31]
Consider the function f(x)=x^{1/3}, which has derivative f'(x)=\dfrac13x^{-2/3}.

The linear approximation of f(x) for some value x within a neighborhood of x=c is given by

f(x)\approx f'(c)(x-c)+f(c)

Let c=64. Then (63.97)^{1/3} can be estimated to be

f(63.97)\approxf'(64)(63.97-64)+f(64)
\sqrt[3]{63.97}\approx4-\dfrac{0.03}{48}=3.999375

Since f'(x)>0 for x>0, it follows that f(x) must be strictly increasing over that part of its domain, which means the linear approximation lies strictly above the function f(x). This means the estimated value is an overestimation.

Indeed, the actual value is closer to the number 3.999374902...
4 0
3 years ago
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